DC Circuits Episode 2: Charge and Current Part 2

00:46:49
https://www.youtube.com/watch?v=1T2BGrDbC6g

Ringkasan

TLDRDans cet épisode, le concept de charge et de courant est approfondi à travers la résolution de problèmes basés sur des graphiques de charge par rapport au temps. Les présentateurs décrivent comment calculer le courant en prenant la dérivée de la charge (Q) par rapport au temps (t), et fournissent des exemples concrets de calculs de charges totales à partir de graphiques de courant à l'aide de formules géométriques. Cela consiste à estimer des aires sous ces graphiques en utilisant des formes comme des rectangles et des trapèzes. Les règles sur le comportement des courants constants et leur représentation graphique sont également expliquées. Cet épisode vise à renforcer la compréhension des fondements des circuits en se concentrant sur les différentes manières d'appliquer les équations de courant et de charge.

Takeaways

  • ⚡ La charge est dérivée par rapport au temps pour déterminer le courant.
  • 📈 Le courant peut être calculé à partir de la pente d'un graphique de charge.
  • 🔄 L'intégration de la courbe de courant donne la charge totale.
  • 📐 Utilisez des formes géométriques pour simplifier le calcul des aires sous les courbes.
  • 🟡 Un graphique de courant constant apparaîtra comme une ligne droite.
  • 📊 Les charges peuvent être trouvées avec les aires sous courbes pour des formes régulières.
  • 💡 Des graphiques irréguliers nécessitent des intégrations pour le calcul de charge.
  • ✅ L'utilisation de la formule d'aire pour les trapèzes et rectangles facilite le calcul.
  • ⌚ Les unités de charge se retrouvent en coulombs.
  • 🔁 Les concepts de charge et courant sont fondamentaux pour comprendre les circuits.

Garis waktu

  • 00:00:00 - 00:05:00

    Introduction à l'épisode 2, qui traite de la charge et du courant, en référence à l'épisode 1 pour les concepts de base.

  • 00:05:00 - 00:10:00

    Début de la résolution des problèmes liés à la charge et au courant avec un graphique de charge en fonction du temps, recherche de courant à t = 1 ms, 6 ms et 10 ms en utilisant la dérivée de la charge par rapport au temps.

  • 00:10:00 - 00:15:00

    Calcul du courant à t = 1 ms en déterminant le taux de changement ou la pente de la ligne sur le graphique, on trouve 40 A comme courant.

  • 00:15:00 - 00:20:00

    Pour t = 6 ms, on observe que le graphique est horizontal, donc le courant est 0 A, ce qui correspond à une absence de changement dans la charge.

  • 00:20:00 - 00:25:00

    Pour t = 10 ms, le graphique montre une pente négative, donc le courant est -40 A, indiquant que la charge diminue.

  • 00:25:00 - 00:30:00

    Transition vers un nouveau problème avec un graphique de la charge, construction du graphique du courant en dérivant la charge par rapport au temps pour différents intervalles.

  • 00:30:00 - 00:35:00

    Calcul des courants pour chaque intervalle de temps en trouvant les pentes appropriées sur le graphique, concluant que le courant est de 25 A, -25 A et 25 A pour chaque intervalle respectivement.

  • 00:35:00 - 00:40:00

    Introduction d'un nouveau problème où le courant est donné, calcul de la charge totale en utilisant l'intégrale du courant sur le temps, et mention de l'aire sous la courbe pour des formes géométriques régulières comme les trapèzes.

  • 00:40:00 - 00:46:49

    Calcul final de la charge totale à partir des aires sous le courant pour plusieurs intervalles, avec une dernière note sur l'intégration de graphiques irréguliers.

Tampilkan lebih banyak

Peta Pikiran

Video Tanya Jawab

  • Quelle est la formule pour calculer le courant à partir de la charge ?

    Le courant est la dérivée de la charge par rapport au temps (I = dQ/dt).

  • Comment déterminer la charge totale à partir d'un graphique de courant ?

    La charge totale est calculée en intégrant le courant par rapport au temps, ce qui revient à trouver l'aire sous la courbe du graphique de courant.

  • Quelles géométries peuvent être utilisées pour calculer l'aire ?

    Vous pouvez utiliser des rectangles et des trapèzes pour calculer l'aire sous la courbe si les formes sont régulières.

  • Comment interpréter un courant constant dans un graphique de courant ?

    Un courant constant apparaîtra comme une ligne horizontale sur le graphique, indiquant que le taux de flux de charge ne change pas.

  • Que se passe-t-il si le graphique de courant n'est pas régulier ?

    Si le graphique est irrégulier, vous devez utiliser des méthodes d'intégration pour trouver la charge.

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Gulir Otomatis:
  • 00:00:04
    Hello Good
  • 00:00:05
    day so our topic is all about this is
  • 00:00:10
    circuits episode 2 which is part 2 ng
  • 00:00:14
    topic natin which is all about charge
  • 00:00:18
    and current Okay so meron na tayong
  • 00:00:23
    episode 1 part one for the same topic
  • 00:00:25
    charge and current So kung hindi niyo pa
  • 00:00:28
    napapanood is ni-link ko na lang sa
  • 00:00:30
    description para alam niyo na yung
  • 00:00:33
    concepts na di-discuss natin dito sa
  • 00:00:36
    topic na charge and current so ito yung
  • 00:00:38
    mga na-discuss natin doon sa part one
  • 00:00:41
    Okay and then as promise magso-sorry
  • 00:01:03
    number f
  • 00:01:05
    Okay sige so mag-solve tayo ng more
  • 00:01:07
    problems let's continue sulat ko muna
  • 00:01:10
    problem number
  • 00:01:16
    si the charge
  • 00:01:21
    entering a
  • 00:01:24
    certain
  • 00:01:26
    element is
  • 00:01:30
    shown
  • 00:01:34
    below find the
  • 00:01:38
    current
  • 00:01:40
    at a time t = 1
  • 00:01:46
    ah
  • 00:01:47
    millisecond p time t qu 6 millisecond
  • 00:01:53
    and c t 10 mise tapos meron tayong wave
  • 00:01:59
    form ng charge
  • 00:02:04
    versus
  • 00:02:07
    time So you
  • 00:02:10
    have 1 2 or Let's have 2 4 6 8
  • 00:02:25
    10 12
  • 00:02:45
    so 0 2 4 6 8 10
  • 00:02:51
    12 14 yung time natin horizontal axis is
  • 00:02:57
    in
  • 00:02:58
    millisecond tapos ung yung vertical axis
  • 00:03:01
    is yung charge Q of t measured in milc
  • 00:03:05
    colum then meron tayong value na
  • 00:03:10
    80 Okay so yung graph is
  • 00:03:24
    ganito Okay so the charge entering a
  • 00:03:28
    certain element is shown below find the
  • 00:03:32
    current AT T A 1 MC b t6 m and CT 10 MC
  • 00:03:40
    so given yung graph Paano natin
  • 00:03:43
    hahanapin
  • 00:03:46
    yung charge I mean Paano natin
  • 00:03:51
    hanapin yung current I
  • 00:03:55
    Okay kasi sa mga previous problem I'm
  • 00:03:58
    given is ung equation nng charge right Q
  • 00:04:02
    of t Paano kapag graph so apply pa rin
  • 00:04:05
    natin ung formula or concept na ' ba
  • 00:04:08
    yung current is derivative ng charge
  • 00:04:12
    with respect to time Okay so at a t equ
  • 00:04:19
    1
  • 00:04:21
    mise So nasaan yung 1 millisecond dito
  • 00:04:24
    sa sa horizontal axis dito Right ito ung
  • 00:04:28
    one So ibig
  • 00:04:30
    sabihin makukuha natin ung charge I mean
  • 00:04:34
    ung current AT T is equ to 1 millisecond
  • 00:04:38
    using this part of the graph Okay so
  • 00:04:42
    Anong kukuhain natin doon sa graph yung
  • 00:04:45
    slope Okay
  • 00:04:47
    kasi yung current
  • 00:04:50
    is time derivative nung Q with respect
  • 00:04:54
    to or derivative ng Q with respect to t
  • 00:04:56
    which is also the slope of the line for
  • 00:05:01
    this portion of the graph Okay remember
  • 00:05:04
    yyung derivative is the slope of the
  • 00:05:07
    tangent line to the curve at a point so
  • 00:05:10
    dahil given naman Iyung equation nung Q
  • 00:05:12
    of t natin as a function of time ito
  • 00:05:14
    Iyung graph niya ' ba So dito sa portion
  • 00:05:17
    ng graph na which is just a line okay
  • 00:05:23
    pag kinuhan natin yung slope nito yun na
  • 00:05:26
    rin yung derivative or yun na rin ung
  • 00:05:29
    current or derivative nung with respect
  • 00:05:32
    to time or yung slope
  • 00:05:34
    nung nung curve natin itong Q of t at a
  • 00:05:40
    point where t is equ 1 m So ibig sabihin
  • 00:05:44
    kukuh lang natin yung slope yun lang
  • 00:05:46
    lagi okay So paano ba yung slope price
  • 00:05:50
    over
  • 00:05:51
    Run
  • 00:05:53
    so delta Q bale over delta t
  • 00:06:00
    so kuh natin yung mga end points nitong
  • 00:06:03
    line so we have the origin for this
  • 00:06:06
    point and then we have the coordinate
  • 00:06:12
    2
  • 00:06:15
    80 Okay so we can have q2 - q1 over t2 -
  • 00:06:23
    T1 delta Q over delta
  • 00:06:27
    t so given the point na ' tsaka ito
  • 00:06:31
    let's say ito si q1 ah q2
  • 00:06:36
    ah q2 Tapos T1 ah t2 I mean Tapos ito si
  • 00:06:44
    T1 q1 Okay so plug in in the formula q2
  • 00:06:50
    is
  • 00:06:52
    80 -
  • 00:06:55
    q1 0
  • 00:06:57
    Okay divided by t2 which is
  • 00:07:02
    2 yung
  • 00:07:04
    coordinate Min T1 which
  • 00:07:07
    is which is
  • 00:07:11
    zero
  • 00:07:17
    Okay so we have 80 - 0 That's just 80
  • 00:07:22
    over 2 - 0 which is 2 so 80 / 2 that's
  • 00:07:28
    40 okay
  • 00:07:31
    so ang unit natin kasi dito is
  • 00:07:34
    milli colum
  • 00:07:38
    right tapos dito is
  • 00:07:41
    millisecond so ma-cancel niya lang yung
  • 00:07:43
    milli magiging colum per second
  • 00:07:48
    or 40
  • 00:07:50
    amps Okay so yung sagot sa part A is 40
  • 00:07:56
    amps
  • 00:08:02
    delete
  • 00:08:08
    natin So this is 2
  • 00:08:14
    80 next Dito naman sa part
  • 00:08:20
    B AT T is equ 6 mise
  • 00:08:30
    so Gan ulit check niyo muna kung saang
  • 00:08:32
    portion ng
  • 00:08:33
    gra malocate yung 6 m ba sa saan siyang
  • 00:08:40
    por ng gra dito sa line na
  • 00:08:42
    to
  • 00:08:44
    Okay so yan yung kukuhaan natin ng slope
  • 00:08:48
    so kapag horizontal
  • 00:08:50
    line bale yung end points nitong line is
  • 00:08:55
    28a b 10
  • 00:09:02
    kama 80
  • 00:09:04
    din Okay pag Kinuha mo yung slope niyan
  • 00:09:07
    so current is again delta Q over delta t
  • 00:09:13
    so let's say ito si 2 ito si t2 ito
  • 00:09:17
    si q2 ito si
  • 00:09:20
    T1
  • 00:09:23
    q1 so q2 q2 - q1
  • 00:09:29
    div by t2 - T1 so q2 is
  • 00:09:36
    80 Min q1 is 80 pa rin
  • 00:09:41
    right div t2 is
  • 00:09:46
    10 min T1 is
  • 00:09:50
    2 so 80 - 80 0 10 -
  • 00:09:57
    2 8 so 0 / 8
  • 00:10:01
    is z0 okay
  • 00:10:04
    amps okay which makes sense kasi ' ba
  • 00:10:08
    kapag horizontal line tayo sa analytic
  • 00:10:12
    geometry natin Ano ba yung slope ng
  • 00:10:15
    horizontal line zero right So kaya zero
  • 00:10:20
    din dapat yung
  • 00:10:23
    current wala ka kasing change sa Q ung
  • 00:10:29
    tak mo is zero or yung rice is
  • 00:10:35
    zero Okay next Dito naman sa c 10
  • 00:10:41
    mise t is 10
  • 00:10:46
    mise so Saang portion naman tayo ng
  • 00:10:49
    graph titingin kung yung time is 10
  • 00:10:52
    millisec ito si si time t 10 millisecond
  • 00:10:56
    ' ba e Dito siya sa graph na'to or sa
  • 00:11:00
    part n graph na which is align Okay
  • 00:11:05
    align pa rin so pag kinuhan natin yung
  • 00:11:08
    slope niyan check niyo yung mga
  • 00:11:10
    coordinates n end point so ito is 10 10
  • 00:11:16
    10 80 Tapos ito is
  • 00:11:21
    120 Okay so yung
  • 00:11:25
    slan current is equ del q
  • 00:11:30
    t q2 - q1 / t2 - T1 so let's say ito si
  • 00:11:39
    ito si
  • 00:11:40
    t2 Okay which is coordinate
  • 00:11:44
    is T1 q1 t's ito I mean ito si si2 right
  • 00:11:52
    so t2 q2 t's ito si 1 T1 q1
  • 00:11:59
    nio yung slope so q2 - q1 or 0 -
  • 00:12:04
    80 right so 0 - 80
  • 00:12:10
    div t2 - T1 or 12 -
  • 00:12:19
    10 so we have 0 -
  • 00:12:23
    80 -80 div 12 - 10 that's 2 which is -
  • 00:12:32
    80 di
  • 00:12:34
    2 - 40 So amps So ibig sabihin yung
  • 00:12:40
    current is - 40 so negative siya kasi
  • 00:12:43
    yung slope nga is negative kasi ba kapag
  • 00:12:47
    yung line natin is paganito yung
  • 00:12:49
    orientation ang slope niyan is negative
  • 00:12:52
    unlike pag ganito yung orientation line
  • 00:12:55
    ang slope niya is positive kaya dito sa
  • 00:12:57
    part A ang nakuhang slope is positive
  • 00:13:01
    which is yung current na 40 amp Tapos
  • 00:13:04
    ito sa C negative
  • 00:13:11
    Okay Okay
  • 00:13:14
    next
  • 00:13:17
    number number
  • 00:13:22
    7 the
  • 00:13:26
    charge flowing
  • 00:13:31
    in a
  • 00:13:33
    wire is
  • 00:13:37
    platted in the figure
  • 00:13:44
    below
  • 00:13:50
    sketch the
  • 00:13:55
    corresponding
  • 00:13:58
    current so meron tayong flat uli nung
  • 00:14:02
    charge Q as a function of
  • 00:14:07
    time so we have 0 2 4 6 8 10 so Iyung
  • 00:14:14
    Time natin is in second t's we have 50
  • 00:14:19
    dito - 50
  • 00:14:23
    dito So this is the Q of
  • 00:14:26
    t measured in column
  • 00:14:30
    So yung graph is
  • 00:14:34
    ganito parang hindi pantay yung line
  • 00:14:40
    natin okay ganyan yung
  • 00:14:47
    graph Okay so This is 02 4
  • 00:14:54
    68 Okay Paano daw kapag given yung
  • 00:14:59
    nung charge versus
  • 00:15:03
    time As shown below As shown
  • 00:15:09
    here sketch the corresponding current
  • 00:15:13
    Okay sketch the corresponding current so
  • 00:15:16
    apply pa rin natin yung concept ba
  • 00:15:21
    yung na yung current is the
  • 00:15:26
    derivative derivative ng
  • 00:15:29
    Q with respect to time so pag pinat
  • 00:15:33
    natin
  • 00:15:35
    ngayon yung
  • 00:15:42
    Cent Sige draw tayo
  • 00:15:46
    ng
  • 00:15:50
    another axis this
  • 00:15:53
    time
  • 00:15:55
    current versus time
  • 00:16:09
    Okay so using the formula na yung
  • 00:16:12
    current is the derivative n q with
  • 00:16:16
    respect to time or siya yung slope right
  • 00:16:20
    it is also the slope based sa previous
  • 00:16:23
    problem
  • 00:16:24
    din excuse so kuhain niyo lang yung
  • 00:16:31
    for the same time interval let's say
  • 00:16:35
    dito dito sa time interval na from 0 to
  • 00:16:40
    2 so gayahin nio yung paghati
  • 00:17:01
    Okay so This is 2 This
  • 00:17:05
    is 4 This is 6 and this is
  • 00:17:10
    8
  • 00:17:12
    Okay so dito sa portion na to graph Q of
  • 00:17:16
    Hanapin niyo yung slope ano yung slope
  • 00:17:20
    nito which is Ito kasing point na is 250
  • 00:17:29
    so for interval 0 to
  • 00:17:32
    2 for 0 less
  • 00:17:36
    than t l 2 ano yung current natin yung
  • 00:17:42
    delta Q over delta t which is q2 - q1
  • 00:17:48
    over t2 - T1 so ito
  • 00:17:52
    yung natin
  • 00:17:54
    250 then yung 1 is itong origin
  • 00:18:00
    0,0 so q2 is
  • 00:18:04
    50 Min q1 is
  • 00:18:09
    0 div t2 is
  • 00:18:14
    2 Min T1 is
  • 00:18:18
    0 so 50 Min 0 is 50 div 2-0 2 or 25
  • 00:18:28
    Okay so ang unit natin
  • 00:18:31
    is kasi colum lang ' ' ba 50
  • 00:18:35
    colum / 2 second so 50 / 2 25 colum per
  • 00:18:43
    second or 25 amps so therefore ito yung
  • 00:18:48
    fixed slope for the interval 0 to 2 Okay
  • 00:18:54
    so ung current natin is 25 amps for this
  • 00:18:58
    time in interval So from this interval
  • 00:19:01
    from 0 to 2 fix yung current na let's
  • 00:19:04
    say nandito na lang ito yung level nung
  • 00:19:08
    25 amps Okay horizontal line siya
  • 00:19:14
    Okay ito yyung corresponding graph
  • 00:19:18
    next Okay so Dito
  • 00:19:23
    naman dito sa interval na to
  • 00:19:29
    Okay ano naman yung slope
  • 00:19:32
    niyan so ito yung end point nung isa
  • 00:19:35
    ta's ito ang coordinate niya is
  • 00:19:39
    4,0 so kuhain yung
  • 00:19:43
    slope for 2 l t l
  • 00:19:48
    4 I is delta Q / delta
  • 00:19:53
    t q2 - q1 / t2 - T1
  • 00:19:59
    So yung point naman natin is 40 saka
  • 00:20:04
    250
  • 00:20:08
    Okay so ano yung ano natin diyan ano
  • 00:20:13
    yung
  • 00:20:14
    magiging
  • 00:20:17
    slop so let's say ito si
  • 00:20:20
    q2 si
  • 00:20:23
    T1 si q1 si T1
  • 00:20:30
    Sige kuhain natin yung point so
  • 00:20:34
    40
  • 00:20:38
    and
  • 00:20:41
    2,50 so ito si
  • 00:20:45
    q2
  • 00:20:49
    t2
  • 00:20:52
    Tapos ito si q1 ito si T1 so using the
  • 00:20:58
    formula
  • 00:20:59
    q2 is
  • 00:21:01
    0 - q1 is 50 div
  • 00:21:07
    t2 is
  • 00:21:10
    4 -
  • 00:21:12
    T1 is
  • 00:21:15
    2 so 0 - 50 - 50 div 4 - 2 2 So that's -
  • 00:21:26
    25 So saan naman yung ne
  • 00:21:30
    25 so dito let's say - 25 so for this
  • 00:21:35
    interval
  • 00:21:37
    from 2 2 to 4 ang value n current is fix
  • 00:21:43
    at nega
  • 00:21:45
    25
  • 00:21:48
    Okay
  • 00:21:50
    next for this interval
  • 00:21:54
    naman 4 to
  • 00:21:57
    6 which is ang end point is 4,0 tsaka
  • 00:22:02
    ano to
  • 00:22:04
    6
  • 00:22:08
    -50 Okay so kung ain yung slope so for
  • 00:22:14
    interval 4 l t l
  • 00:22:19
    6 so current is delta Q / delta
  • 00:22:23
    t so q2 - q1 / t2 - T1 So ano ung mga
  • 00:22:30
    point
  • 00:22:31
    natin 6
  • 00:22:34
    -50 t saka
  • 00:22:44
    40 6 -50 and
  • 00:22:49
    4,0 so ito si
  • 00:22:51
    q2 t2 ito si q1
  • 00:22:56
    T1 plugin
  • 00:22:59
    q2 is -
  • 00:23:01
    50 - q1 is 0 div t2 is
  • 00:23:10
    6
  • 00:23:12
    6 - T1 is
  • 00:23:15
    4 so - 50 - 0 - 50 pa rin 6 - 4 2 which
  • 00:23:24
    is - 50 / 2 that's - 25 amps pa rin so
  • 00:23:31
    nandito pa rin siya sa same level for
  • 00:23:34
    this
  • 00:23:35
    interval 4 to 6 - 25 pa rin then last
  • 00:23:41
    yung interval
  • 00:23:43
    from 6 to 8 so ito yung end point nung
  • 00:23:48
    line 6 -50 tapos ito
  • 00:23:52
    is um 80
  • 00:23:58
    so for 6 l t less
  • 00:24:03
    8 so I is delta Q over delta t or q2 -
  • 00:24:10
    q1 / t2 - T1 so ang gagamitin nating
  • 00:24:14
    point ngayon ay
  • 00:24:17
    80 saka
  • 00:24:24
    6-5 so
  • 00:24:26
    80 and
  • 00:24:28
    6
  • 00:24:30
    ne
  • 00:24:32
    50 so let's say ito si
  • 00:24:36
    t2 q2 ito si
  • 00:24:41
    T1
  • 00:24:42
    q1 so substitute dito we have q2 is 0 -
  • 00:24:49
    q1 is
  • 00:24:51
    -50 div t2 8 - T1
  • 00:24:56
    6 so negative of - 50 + 50 div 8 - 6
  • 00:25:04
    which is
  • 00:25:05
    2 so 50 / 2 that's 25 amps so fix uli
  • 00:25:12
    constant current 25 for this interval 6
  • 00:25:16
    to 8 so dito
  • 00:25:19
    siya Okay so therefore ito Iyung graph
  • 00:25:22
    nung
  • 00:25:23
    ating
  • 00:25:25
    current Okay kapag
  • 00:25:29
    Sige draw natin in
  • 00:25:35
    red
  • 00:25:39
    yan tapos
  • 00:25:41
    yan okay for the
  • 00:25:44
    given graph nitong charge versus time
  • 00:25:48
    ito yung magiging graph nung current
  • 00:26:00
    Okay
  • 00:26:01
    next number
  • 00:26:07
    8 for number 8 the
  • 00:26:14
    current
  • 00:26:17
    flowing
  • 00:26:20
    pas a
  • 00:26:23
    point in a
  • 00:26:27
    device is
  • 00:26:32
    shown in Figure
  • 00:26:41
    below
  • 00:26:45
    Calculate the total
  • 00:26:51
    charge through the
  • 00:26:55
    point okay Meron tayong graph uli this
  • 00:26:59
    time current versus time
  • 00:27:04
    naman So
  • 00:27:06
    1
  • 00:27:08
    2 Time natin is in millisecond tapos
  • 00:27:12
    meron tayong current I in
  • 00:27:16
    milliamps So this is
  • 00:27:19
    10 then Iyung graph is ganito
  • 00:27:35
    Okay so the current flowing past a point
  • 00:27:39
    in a device is shown in Figure below so
  • 00:27:42
    ang graph ngayon natin is current versus
  • 00:27:44
    time shown here Calculate the total
  • 00:27:48
    charge so Paano kapag total charge ang
  • 00:27:51
    pinapahanap
  • 00:27:53
    so apply naman natin yung
  • 00:27:56
    formula na yung charge
  • 00:28:00
    is the integral of
  • 00:28:03
    idt from initial time t KN to final time
  • 00:28:09
    t plus whatever is the initial charge Q
  • 00:28:14
    AT T KN Okay so assuming itong Q of t KN
  • 00:28:19
    natin is
  • 00:28:20
    zer Okay so ito na lang yung gagamitin
  • 00:28:23
    nating formula kasi wala namang binigay
  • 00:28:25
    na initial charge AT T not right assume
  • 00:28:29
    natin na
  • 00:28:30
    zero so ang gagamitin nating formula na
  • 00:28:33
    lang is integral ng idt from t KN to t
  • 00:28:38
    So paano kapag given yung graph hindi
  • 00:28:40
    yung equation nung
  • 00:28:43
    current so apply natin yung concept na '
  • 00:28:47
    ba yung
  • 00:28:48
    integral application ng integral is the
  • 00:28:51
    area bounded by curves right So kung
  • 00:28:54
    i-in grr natin ' itong
  • 00:28:58
    graph na to from Bale ang initial time
  • 00:29:01
    is zer origin hanggang final time t So
  • 00:29:06
    yung T natin dito is
  • 00:29:09
    0 yung T natin is 2 so integrate natin
  • 00:29:13
    from 0 to 2 yung
  • 00:29:16
    idt which is yung i na to is represented
  • 00:29:19
    by the
  • 00:29:21
    graph so dahil yung integral from 0 to 2
  • 00:29:26
    ng idt is the same as
  • 00:29:28
    area area na' okay pag shade
  • 00:29:44
    natin pwede na lang nating applyan ng
  • 00:29:48
    geometric formula for the area nitong
  • 00:29:51
    shaded region espcially kung yung region
  • 00:29:56
    naman natin or yung figure is
  • 00:30:00
    um
  • 00:30:02
    ah tawag dito is pwedeng maapply yan ng
  • 00:30:05
    formula using yung mga geometric figure
  • 00:30:08
    right kasi Ano ba to this is Actually a
  • 00:30:11
    trapezoid
  • 00:30:15
    right So pwede nating gamitan ng formula
  • 00:30:18
    ng area for trapezoid which is Anong
  • 00:30:21
    area ng
  • 00:30:23
    trapezoid
  • 00:30:25
    1/2 times height times base 1 plus base
  • 00:30:29
    2 so ito yung base
  • 00:30:32
    1 ito yung base
  • 00:30:36
    2 Okay tapos yung height
  • 00:30:41
    ISO okay Kasi this is perpendicular
  • 00:30:46
    right Okay so makukuha agad natin yung
  • 00:30:49
    total
  • 00:30:50
    charge so total charge is 1/2
  • 00:30:58
    ano yung height natin So
  • 00:31:01
    that's 10 right ito yun
  • 00:31:07
    10 so 10 yung
  • 00:31:10
    height
  • 00:31:12
    times yung sum nung base 1 saka base 2
  • 00:31:16
    SAO yung base 1 Anong unit nito or ilan
  • 00:31:20
    yung length from 1 to 2 ibig sabihin How
  • 00:31:25
    many units 2 - 1 or 1 right So yung base
  • 00:31:30
    1 is 1
  • 00:31:31
    unit plus yung base two
  • 00:31:35
    ito
  • 00:31:37
    from 0 to 2 So that's 2 - 0 or 2 units
  • 00:31:44
    so yan yung base 2
  • 00:31:47
    natin So kapag kinompute natin to 1/2
  • 00:31:51
    Tim 10 that's 5 Tim 1 + 2 3 which is 5 3
  • 00:32:00
    or
  • 00:32:01
    15 Okay 15 Anong unit
  • 00:32:05
    natin kasi we have
  • 00:32:08
    milliamp and then we have
  • 00:32:12
    millisecond so kapag multiply
  • 00:32:15
    mo yung kasi ba Q is the product ng I
  • 00:32:21
    Tim
  • 00:32:22
    time So yung current mo is naka milliamp
  • 00:32:28
    tapos yung time mo is naka
  • 00:32:30
    millisecond that's milli Tim milli 10
  • 00:32:35
    to3 Tim 10
  • 00:32:38
    to3 that's
  • 00:32:41
    106 right ang unit amp second
  • 00:32:46
    is charge Okay so 10 to 6 colum which is
  • 00:32:51
    kapag ginamitan mo ng prefix yung 10 to
  • 00:32:56
    6 micro y
  • 00:32:59
    right so ang total charge is 15 micr
  • 00:33:05
    colum Okay
  • 00:33:07
    using formula for the area n trap Pero
  • 00:33:11
    in case na na yung equation or yung
  • 00:33:14
    graph nung current natin is hindi
  • 00:33:17
    regular regular shape halimbawa ah let's
  • 00:33:21
    say yung graph is naging ganito Okay yan
  • 00:33:26
    yung gagamitan niyo ngayon ng integral
  • 00:33:29
    okay pag irregular ung shape nung graph
  • 00:33:33
    Pero kapag mga regular shape naman like
  • 00:33:35
    trapezoid rectangle square triangle
  • 00:33:39
    Pwede niyo na lang gamitan ng formula
  • 00:33:41
    for the area para mas
  • 00:33:44
    madala
  • 00:33:45
    Okay
  • 00:33:51
    next number
  • 00:33:55
    nine so gann uli
  • 00:34:01
    f or sulat ko
  • 00:34:09
    muna the
  • 00:34:12
    current through an
  • 00:34:15
    element is
  • 00:34:18
    shown
  • 00:34:23
    below determine
  • 00:34:28
    the total
  • 00:34:30
    [Musika]
  • 00:34:34
    charge that
  • 00:34:37
    passed
  • 00:34:40
    through the element
  • 00:34:44
    at so meron tayong tatlong case at t equ
  • 00:34:49
    1 second B AT T equ 3 second C AT
  • 00:34:55
    T 5 second Eto yung
  • 00:35:17
    [Musika]
  • 00:35:25
    graph na lang
  • 00:35:36
    So this is 5 This is
  • 00:35:42
    10 tapos 1 2
  • 00:35:46
    3 4 5 6 so time is measured in
  • 00:35:53
    second current is measured in
  • 00:35:56
    amps so
  • 00:36:02
    10
  • 00:36:07
    2
  • 00:36:09
    4 5 1 2 3 4 ah mala mala mala
  • 00:36:21
    mala 4 f
  • 00:36:24
    [Musika]
  • 00:36:28
    ito yung
  • 00:36:30
    f ito yung five Okay tapos This Is
  • 00:36:38
    Zero so determine the current or the
  • 00:36:42
    current through an element is shown
  • 00:36:44
    below again graph uli nung current
  • 00:36:46
    versus time determine the total charge
  • 00:36:50
    that pass through the element so charge
  • 00:36:52
    uli
  • 00:36:54
    At Time a for a time t is 1 second So
  • 00:36:59
    ibig sabihin hanggang ano lang tayo from
  • 00:37:02
    zer to 1 Okay 1 second So ano lang yung
  • 00:37:07
    graph natin
  • 00:37:09
    diyan Ito lang Okay so Yan lang yung
  • 00:37:13
    hahanapan natin ng area kasi charge uli
  • 00:37:18
    yung hinahanap ' ba Pag charge is yung
  • 00:37:20
    area under the
  • 00:37:22
    curve so for a total charge is So anong
  • 00:37:28
    area nito area which is
  • 00:37:33
    rectangle length times wid lang okay
  • 00:37:37
    yung length is
  • 00:37:39
    ito which is 10
  • 00:37:43
    units so 10
  • 00:37:46
    amps di ba 10 amps times the
  • 00:37:52
    Wi which is 1 unit from 1 Ah from zer to
  • 00:37:57
    1 1 Unit 1
  • 00:38:01
    second Okay so that's 10 amps Tim 1
  • 00:38:05
    second
  • 00:38:06
    or 10
  • 00:38:12
    colum for part
  • 00:38:16
    B T is 3 seconds naman So from 0 to 3 So
  • 00:38:24
    ano yung graph natin
  • 00:38:29
    hanggang
  • 00:38:32
    dito hanggang dito
  • 00:38:37
    Okay so shadan natin lahat nung
  • 00:38:42
    area enclosed from time 0 to time t equ
  • 00:38:49
    3
  • 00:38:51
    Okay
  • 00:38:54
    so dagdag na lang natin onong area na
  • 00:38:58
    to dito sa area nung rectangle kasi
  • 00:39:02
    Kasama rin to ' ba So
  • 00:39:05
    4b Q is so automatic kasama na to yyung
  • 00:39:10
    area na 10 which is equivalent to 10
  • 00:39:14
    colum right plus ito
  • 00:39:18
    pa so hatiin natin into 2
  • 00:39:23
    pwedeng ito muna
  • 00:39:27
    1 tapos
  • 00:39:29
    q2 so dito sa q2 q1 That's a trapezoid
  • 00:39:35
    right so
  • 00:39:37
    1/2
  • 00:39:39
    height B1
  • 00:39:42
    B2 So ano yung height ito yung height
  • 00:39:46
    yung
  • 00:39:47
    perpendicular right which is 2
  • 00:39:52
    2-1 1 unit okay
  • 00:39:57
    So this is 1 unit times yung b1 let's
  • 00:40:03
    say ito yung
  • 00:40:04
    b1 which is
  • 00:40:07
    10 Okay
  • 00:40:09
    10
  • 00:40:12
    units plus yung
  • 00:40:16
    B2 it
  • 00:40:18
    naman which is
  • 00:40:21
    5 5 units
  • 00:40:25
    right Plus
  • 00:40:29
    5 Okay ito yung q1 plus ito namang
  • 00:40:36
    q2 ano lang siya
  • 00:40:41
    rectangle length
  • 00:40:43
    Tim ano yung
  • 00:40:46
    length length natin is
  • 00:40:49
    Ito ba 5
  • 00:40:54
    units so
  • 00:40:56
    5 times the wid yyung wid naman is yung
  • 00:41:00
    mas maliit
  • 00:41:02
    ito which is from 2 to 3 or 3 - 2
  • 00:41:07
    1 1
  • 00:41:10
    unit so bale Meron tayong 10 colum plus
  • 00:41:15
    So ilan
  • 00:41:17
    to
  • 00:41:19
    1/2 1/2 ng 10 +
  • 00:41:24
    5
  • 00:41:26
    15 15 / 2
  • 00:41:31
    7.5 colum + 5 *
  • 00:41:35
    1
  • 00:41:38
    5 so 10 colum + 7.5 colum + 5 colum
  • 00:41:46
    22.5
  • 00:41:49
    colum okay last ung
  • 00:41:54
    c c is AT T is equal to 5
  • 00:41:59
    seconds so
  • 00:42:00
    hanggang 5 na from 0 to 5 yung region or
  • 00:42:05
    yung area natin So shsh na natin
  • 00:42:12
    lahat okay so bale kasama na agad
  • 00:42:16
    to yung area from 0 to 3 which is
  • 00:42:21
    nacompute na
  • 00:42:23
    natin sa part B 22
  • 00:42:29
    22.5 right So yung total charge is
  • 00:42:33
    kasama na agad to 22.5 colum plus yung
  • 00:42:39
    added area na lang na to let's say
  • 00:42:42
    q3 which is a trapezoid
  • 00:42:45
    uli Okay so area is 1/2 he Tim b1 plus
  • 00:42:52
    B2 So ano yung height yung height is ito
  • 00:42:57
    uli which is yung
  • 00:43:01
    perpendicular
  • 00:43:03
    Okay which is 5 units right 5 units
  • 00:43:07
    Iyung
  • 00:43:09
    height so Iyung height is 5 units
  • 00:43:13
    substitute ano Iyung
  • 00:43:15
    b1 yung b1 let's say ito na
  • 00:43:21
    lang So that's
  • 00:43:23
    from from 4 to 3 right How many units
  • 00:43:29
    yon 4 -
  • 00:43:31
    3 1 unit Okay 1 unit lang to let's say
  • 00:43:35
    ito yung
  • 00:43:37
    b1 so 1 unit plus yung B2 ano yung B2
  • 00:43:44
    ito na yung baba
  • 00:43:48
    right So from 3 to 5 how many length How
  • 00:43:53
    many units is the length 5 - 3 2
  • 00:43:59
    so bale q equ
  • 00:44:03
    22.5 plus so
  • 00:44:06
    1/2
  • 00:44:08
    5 or
  • 00:44:11
    2.5
  • 00:44:12
    Tim 1 +
  • 00:44:15
    2
  • 00:44:18
    3
  • 00:44:21
    right So this is 2.5 3
  • 00:44:27
    Ilan
  • 00:44:31
    yon 15 kasi 15 / 2 yan '
  • 00:44:36
    ba
  • 00:44:43
    7.5 So 22.5 + 7.5 colum eksakto na to na
  • 00:44:52
    30 30
  • 00:44:54
    colum so yan yung sagot sa sa part
  • 00:45:02
    C Okay
  • 00:45:06
    yan so again kung yung figure natin na
  • 00:45:09
    is hindi regular Tulad nito Nagkataon
  • 00:45:13
    kasi na yung graph nung ating current is
  • 00:45:17
    P Kinawa natin yung mga area mga mga
  • 00:45:20
    regular shape right
  • 00:45:23
    rectangle saka trapezoid
  • 00:45:27
    kaya ginamitan na lang natin ng mga
  • 00:45:29
    formula ng area for geometric figure
  • 00:45:31
    Pero kapag irregular let's say ganito
  • 00:45:34
    curve I integrate niyo Okay gamit yung
  • 00:45:37
    formula na charge Q is integral ng idt
  • 00:45:43
    from t not to
  • 00:45:49
    t Okay so i think hanggang dito na lang
  • 00:45:52
    muna yung discussion natin for this to
  • 00:45:56
    peak charge and current so Siguro next
  • 00:46:02
    time di-discuss naman natin is voltage
  • 00:46:07
    energy and Power Okay so isa-isahin
  • 00:46:12
    natin yung mga definition nung
  • 00:46:15
    ah mga
  • 00:46:17
    terminologies na gagamitin natin dito sa
  • 00:46:22
    DC circuit subject okay yung mga current
  • 00:46:26
    voltage
  • 00:46:27
    charge energy power
  • 00:46:30
    etc so y so end ko na yung ating ating
  • 00:46:34
    video tutorial for this topic and see
  • 00:46:38
    you sa next live natin
Tags
  • charge
  • courant
  • circuits
  • problèmes de circuits
  • dérivée
  • intégration
  • temps
  • formules géométriques
  • graphique de courant
  • énergie