00:00:00
okay so as you guys saw from the packet
00:00:02
chapter 13 is all vectors calculus of
00:00:18
vector valued functions like derivatives
00:00:20
and integrals and stuff like that so I'm
00:00:24
good I mean you guys knew that was gonna
00:00:26
come right like it's a calculus class
00:00:30
first thing I want to review and this is
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something we talked about last chapter
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is parametric curves so last chapter we
00:00:42
looked at parametric curves specifically
00:00:44
lines in three space and two space
00:00:48
parametric curves are gonna look like
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this X is going to be some function of T
00:00:52
Y is gonna be some function of T and Z
00:00:56
is gonna be some function of T these are
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gonna represent a space curve in three
00:01:02
space
00:01:09
and of course you could do the same
00:01:11
thing in 2-space well we're gonna be
00:01:14
looking at three space now those
00:01:18
equations represent a path in space that
00:01:29
is traced in a specific direction as T
00:01:41
increases that direction is often
00:01:46
referred to as orientation
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so we didn't focus too much on that but
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as you plugged in your values of T you
00:01:53
got your curve in a specific direction
00:01:56
if you remember talking about the
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equations of lines when you chose T
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values greater than zero you were going
00:02:02
to the right whereas T values less than
00:02:05
zero we're gonna move you to the left on
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your curve last thing I want to review
00:02:12
before we move on is domain your domain
00:02:16
is gonna be all real numbers unless
00:02:18
specified otherwise
00:02:28
okay so the whole reason we need to
00:02:31
review parametric curves is that's going
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to help us with this first section which
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is vector valued functions so next thing
00:02:41
we're going to talk about is vector
00:02:42
valued functions we are not gonna write
00:02:51
out a whole long definition I'm just
00:02:54
gonna show you what's most important
00:02:56
your vector valued function is going to
00:02:59
be called R sometimes it'll be written
00:03:02
as R of T it's going to be a vector
00:03:09
where the the X component is defined by
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some function the Y component is defined
00:03:16
by some function and the Z component is
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defined by some function all three of
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these are called component functions
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of our so here's what's important at any
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given T value R represents a vector
00:03:51
whose initial point is at the origin and
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then the terminal point is going to be
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the point F of T G of T H of T
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[Music]
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so first thing that we're gonna be
00:04:23
interested in is graphs so anytime you
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talked about graphs of course you're
00:04:28
gonna look at the domain and range
00:04:29
domain for these vector valued functions
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is gonna be all real numbers range is
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gonna be a set of vectors most of the
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time your domain is all real numbers
00:04:47
we're gonna look at some cases where
00:04:49
it's not so in terms of a graph of a
00:04:58
vector-valued function so from now on
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I'm going to use V V F that means vector
00:05:04
value function the graph of a vector
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value function is gonna be a curve that
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is traced by connecting what I'm going
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to call the tips of the radius vectors
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so here is an example so with that R of
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T what you're gonna be doing is you're
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gonna be plugging in different values of
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T so let's say you plug in T equals zero
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that might give you this little vector
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right here so let's say that that's R of
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0 so that's what I get when I plug in T
00:05:50
equals zero that I might plug in T
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equals one and I might get this vector
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right here and then maybe I plug in two
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and I get this vector over here okay so
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then the graph of the vector value
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function is when you connect all of
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these tips so it might be a curve like
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this so we call that R of T or just R
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then you put the arrows to show the
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orientation so graph of a vector-valued
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function is really similar to a
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parametric curve it's still a curve and
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it still has orientation just the way
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you graph it is a little bit different
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how we doing so far okay
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we're gonna do a few graphing examples
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and then we'll move on to our next idea
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first example this one is going to be in
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two space R of T is gonna be two cosine
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of T I subtract 3 sine of TJ and I'm
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telling you in this case that T is
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between 0 and 2pi ok so any time you've
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ever learned graphene before or you
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haven't known how to graph something
00:07:28
you've plugged in some points so that's
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what we're gonna do now you're gonna
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plug in some values of T those will give
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you an X component and a y component so
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obviously you want to plug in 0 because
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that's where you start some good ones
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would be PI over 2 pi 3 PI over 2 and 2
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pi if you plug in 0 cosine of 0 is going
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to give us 1 times 2 is 2 sine of 0 is
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going to be 0
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so that gives us the first vector we
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plugged in PI over 2 cosine a cosine of
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PI over 2 is going to be 0 sine of PI
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over 2 is 1 so that gives me negative 3
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so these are the components of the
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vectors that we'll be graphing we plug
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in PI we're gonna get negative 2 0 we
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plug in 3 PI over 2 we'll get 0 3 and
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then 2 pi will give us 2 0
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okay so now we have to graph all of
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these vectors first vector is 2 0 that's
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that vector 0 negative 3 negative 2 0 0
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3 so what is this gonna form no lips so
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this is where we started so we're gonna
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connect the points of our curves or the
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points of our radius vectors rather you
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have to show the orientation so we
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started here heading this direction now
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remember that those are just the radius
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vectors that we chose if we plugged in
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other values there might be a radius
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vector there and there and there etc so
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do we get how this works
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if you wanted to think of it
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parametrically it would be x equals 2
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cosine of T and y equals negative 3 sine
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of T so that's the same function just
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represented parametrically ready for our
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next graphing one ok good this one's in
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3-space so you ready for that
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okay next example R of T is gonna be for
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cosine T comma for sine of T comma T now
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we should have some idea of what this is
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gonna look like if we do it in two space
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for cosine T for sine T based on the
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last example that we did what do we
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think this will give us circle what
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happens when you introduce that Z of T
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it's kind of a cylinder it's like a
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circle that's opening up this will graph
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it but that's a circle but it's gonna be
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moving also okay so same thing from
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before plug in values of T we're gonna
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plug in all the same ones we did before
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so 0 PI over 2 pi 3 PI over 2 and 2 pi
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ok can I trust that you guys can plug
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these in so can I just write them all
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down for you I'm gonna read you the X
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column going down for 0 negative 4 0 for
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the Y column is gonna be 0 for 0
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negative 4 0 Z column is gonna be 0 PI
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over 2 pi 3 PI over 2 2 pi
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okay you all know from our last chapter
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that I am NOT a good artist so go with
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me a little bit on this one okay
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I don't want to hear any comments about
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how my drawing sucks okay okay so first
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point four zero zero it's gonna be that
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one right there then we have zero 4 and
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PI over 2
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ok so 0 4 PI over 2 is about there then
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we have negative 4 0 and PI ok here's my
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suggestion here PI 3.14 is about here I
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would move another dotted line out so
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that you get the perspective right so 0
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or rather or negative 4 is 0 and then PI
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that's about there bless you okay and
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then we have 0 negative 4 3 PI over 2 3
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PI over 2 is about 4.7 1 just about here
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okay and then let's start by connecting
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those
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then there will be another point about
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there
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so do you see how it's a curved wrapping
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around a cylinder so it's helpful maybe
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to I really feel like this drawings not
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that bad it's not guys yeah it's like it
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slinky
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yeah it's a slinky so it's like this
00:14:01
look if you draw on a cylinder the
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cylinder is not part of the graph but
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the graph is wrapping around the
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cylinder good okay if you want to see
00:14:24
the drawing on my notes which is a
00:14:25
little bit better looks like that so we
00:14:32
have the cylinder we're wrapping around
00:14:33
it
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good news for you is that WebAssign
00:14:44
obviously can't force you to sketch
00:14:46
anything so on WebAssign it's gonna be
00:14:48
more of here's the vector valued
00:14:50
function pick the correct graph in your
00:14:53
packet dollars make you sketch questions
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on graphs before we move on no great
00:15:01
here's our next example and this is
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something that we've done before so this
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is not going to be new this next one
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find a vector and parametric equations
00:15:23
for the line segment that joins a which
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is the point 1 negative 3 for 2 B which
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is negative 5 1 7 okay so we did this
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last chapter we talked about if you're
00:15:48
writing the equation of a line this is a
00:15:50
segment but it's the same idea you need
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a vector parallel to your line and you
00:15:53
need a point so we obviously have a
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point we have to to choose from how we
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can find the vector yeah find the vector
00:16:02
joining A to B I'm gonna call that
00:16:04
vector R so really what I mean is AP
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negative 5 minus 1 will give us negative
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6 1 subtract negative 3 is gonna give us
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4 7 subtract 4 is gonna give us 3 so
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then our R of T these will be the slopes
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I decided to use the first point so we
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get 1 subtract 60 negative 3 at 40
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for at 3t so that's the way to write it
00:16:43
as a vector function or a vector valued
00:16:45
function we decided to write it
00:16:49
parametrically X would be 1 minus 6t y
00:16:52
would be negative 3 plus 4 T and Z would
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be 4 plus 3t now that's a line how do we
00:17:01
make it a segment restriction and how do
00:17:05
we restrict T 0 to 1 and this applies to
00:17:13
both the vector valued function and
00:17:15
parametrically you plug in 0 you're
00:17:17
gonna get point a since that's when we
00:17:19
started if you plug in 1 you'll get
00:17:20
point B ok questions before we do
00:17:27
another example know
00:17:37
find a vector function that represents
00:17:51
the curve of the intersection of the
00:17:59
following two equations first one is
00:18:02
going to be x squared ad y squared
00:18:04
equals one second one is y plus Z equals
00:18:09
two okay if we were to graph this first
00:18:17
one the x squared plus y squared equals
00:18:19
one what is that going to look like
00:18:22
cylinder so just want to be a cylinder y
00:18:25
plus Z equals two
00:18:29
that one's a plane
00:18:31
okay so we're taking a plane we're
00:18:33
taking in a cylinder we're gonna
00:18:34
intersect them first thing that we're
00:18:36
gonna do is we are going to start with
00:18:37
that x squared plus y squared equals 1
00:18:40
well what we want to do is write that
00:18:43
parametrically do you guys know how to
00:18:44
write x squared plus y squared equals 1
00:18:46
parametrically
00:18:53
I think back to this example that we did
00:19:00
we talked about if you take away the T
00:19:03
what are you left with me fewer just to
00:19:05
graph that yeah remember how we talked
00:19:11
about this as a circle when you put the
00:19:13
T in though it makes the circle open up
00:19:16
it's not really a circle anymore but
00:19:18
that's the idea okay so for example for
00:19:20
then X is gonna be cosine T y is gonna
00:19:26
be sine of T parametrically that give us
00:19:30
a circle T is gonna be between 0 and 2pi
00:19:38
ok so that takes care of x and y we need
00:19:43
Z now
00:19:49
why plus C so if I solve for Z I get to
00:19:54
subtract Y Y is what I have up here that
00:20:01
sine of T so now I have a parametric
00:20:07
expression for x y&z that takes both
00:20:09
figures into account so our curve then
00:20:13
we want to write it as a vector value
00:20:15
function X is cosine of T so we get
00:20:18
cosine of T I and sign of TJ J add to
00:20:27
subtract sine of T with T being between
00:20:33
0 & 2 pi
00:20:46
questions okay that's not the only
00:20:50
option what you could have done is you
00:20:53
could have solved for X or Y either one
00:20:56
and you would have gotten X in terms of
00:20:59
Y and you could have then plugged it in
00:21:02
does that make sense what I'm saying
00:21:04
without writing it down okay
00:21:06
so sometimes what people do like another
00:21:09
option if we did it over here maybe you
00:21:11
choose X to be T so then if you solved
00:21:15
for y you would get y equals plus or
00:21:18
minus the square root of one minus x
00:21:19
squared from here and you could then
00:21:23
plug in T same thing here you would
00:21:26
solve for Z you would get two minus y
00:21:28
and then you would have to plug in your
00:21:29
expression for y with me okay that just
00:21:36
does not look as nice so you can do it
00:21:38
that way totally fine it's not gonna
00:21:40
look as nice there's some that that's
00:21:42
gonna be the best option if you're
00:21:44
curious this is what those figures look
00:21:48
like so here's the cylinder here's that
00:21:50
plane so you're left with an ellipse so
00:21:54
this is the equation that we just wrote
00:21:57
kind of cool right
00:22:01
like don't have too much energy so they
00:22:04
do
00:22:09
are you guys more excited by the storm
00:22:12
than by my notes right now the lightning
00:22:17
is cool math is cool too okay two other
00:22:24
things we need to talk about we're gonna
00:22:26
talk about well three things domain
00:22:28
limits continuity so our domain example
00:22:34
we are going to find the domain of R of
00:22:42
T R of T is going to be in three space
00:22:46
the first component is the natural log
00:22:49
of the absolute value of 2t minus 1 and
00:22:52
then e to the T is the second component
00:22:55
third component is the square root of T
00:23:00
okay here's what I mean by domain of a
00:23:03
vector valued function domain includes
00:23:06
all values of T for which R is defined
00:23:18
so the basic idea is you're gonna have
00:23:20
to treat all three domains separately or
00:23:23
all three components separately so x y
00:23:27
and z okay y is the easiest e 2t for e
00:23:33
2t what are the values of T for which
00:23:35
that function is defined all real
00:23:40
numbers so based on YT has to be a real
00:23:45
number based on Z so the square root of
00:23:49
T what values is T for what values of T
00:23:52
is that function defined greater than or
00:23:55
equal to zero
00:23:59
okay how do we approach the natural log
00:24:02
of the absolute value of t minus one I
00:24:09
don't want to know the domain right off
00:24:11
the bat I just want to know what do we
00:24:13
need to consider what do we need to
00:24:19
think about first okay
00:24:23
so we know that natural log you only
00:24:25
have positive numbers so anything bigger
00:24:27
than zero so we need the absolute value
00:24:29
of t minus one to be greater than zero
00:24:36
do you remember how to approach problems
00:24:38
like this
00:24:56
okay when are we gonna be equal to zero
00:25:03
let's consider that when T equals one so
00:25:07
this is what I would do is I would
00:25:08
consider a number line when T equals one
00:25:11
we get zero which we don't want when T
00:25:15
is greater than one is that good is that
00:25:17
part of our domain yes when T is less
00:25:21
than one is that part of our domain yes
00:25:26
so any number is okay except T equals
00:25:29
one the domain here is going to be
00:25:31
negative infinity to 1 Union 1 to
00:25:34
infinity so then the overall domain is
00:25:38
going to be the intersection of all
00:25:41
three of those so that one's not helpful
00:25:47
so we can ignore that so we need this to
00:25:50
be true and T to be greater than or
00:25:52
equal to zero so our hotel name then is
00:25:54
gonna be 0 to 1 Union 1 to infinity
00:26:11
does that make sense so you consider it
00:26:14
all three domains separately and then
00:26:15
find where their intersection is okay we
00:26:20
got one more page notes like probably
00:26:22
ten minutes last thing we need to talk
00:26:25
about is limits and continuity starting
00:26:35
with a limit consider R of T to be a
00:26:40
vector valued function with the
00:26:43
components or component functions f of T
00:26:45
G of T and H of T then the limit as T
00:26:56
approaches a of R of T where you find
00:27:02
that limit as you find the limit of each
00:27:04
of the component functions so you're
00:27:07
going to have the limit as T approaches
00:27:09
a of f of T the limit as T approaches a
00:27:14
G of T and then the limit as T
00:27:17
approaches a of H of T and that is as
00:27:24
long as all three limits exist
00:27:44
so here's an example we are going to let
00:27:50
R of T be T squared I add e to the TJ
00:27:58
subtract 2 cosine of PI T ok we are
00:28:06
going to find the limit as T approaches
00:28:10
0 of R of T
00:28:19
okay so if I want to find the limit as T
00:28:22
approaches 0 of R of T I have to take
00:28:26
the limit as T approaches 0 for each of
00:28:29
the component functions so this is gonna
00:28:33
be alright differently the limit as T
00:28:39
approaches 0 of T squared whatever that
00:28:43
is multiplied by I the limit as T
00:28:47
approaches 0 of e to the T multiplied by
00:28:50
J and then the limit as T approaches 0
00:28:56
to cosine PI T all of that times K limit
00:29:04
as T approaches 0 of T squared that's
00:29:06
just 0 so we get 0 I I plug in 0 that
00:29:11
ends up being 1 so plus 1 J I plug in 0
00:29:15
cosine of 0 0 times 2 will give me
00:29:17
negative 2 okay you don't need to write
00:29:24
the 0 I I just wrote it to help you know
00:29:27
where it came from
00:29:37
questions on limits before we do one
00:29:39
more example am I going too quickly for
00:29:44
us
00:29:45
no we're okay okay next example
00:29:53
R of T the first function is 4t cubed
00:30:00
plus 5 divided by 3t cubed plus one
00:30:05
second function is 1 subtract cosine of
00:30:08
T over T third component function is the
00:30:11
natural log T plus 1 that quantity
00:30:14
divided by T we're going to find the
00:30:20
limit as T approaches 0 of R of T
00:30:30
okay so the limit as T approaches 0 of R
00:30:34
of T I'm not gonna write out all of that
00:30:39
again is that okay you just know that
00:30:41
you're looking for the limit of each
00:30:43
component function if we plug in 0 here
00:30:46
we're gonna get 5 over 1 which is 5 if
00:30:51
we plug in 0 here that'll give me a 1 so
00:30:55
1 minus 1 will give us 0 divided by 0
00:31:00
plug in 0 here oh look we get 0/0 again
00:31:05
what do we have to do l'hopital's rule
00:31:08
remember alofi tiles is also when you
00:31:10
have infinity over infinity or plus or
00:31:12
minus infinity over infinity okay so
00:31:16
take the derivative of 1 minus cosine t
00:31:18
what is that sine T so we get sine T
00:31:24
over 1 derivative of natural log of t
00:31:29
plus 101 over T plus 1 and then the
00:31:38
derivative again gives us 1 now we can
00:31:42
plug in 0 again if we plug in 0 out here
00:31:44
we get 0 over 1 which is 0 if we plug in
00:31:48
0 here we get 1 over 1 which is 1
00:31:57
hey how do we feel about limits good all
00:32:02
of this should be fairly intuitive
00:32:04
because it's stuff that you've done
00:32:05
before just apply in a different manner
00:32:07
last thing we need to talk about is
00:32:08
continuity a vector function when I say
00:32:19
a vector function that's the same as a
00:32:20
vector valued function so just know
00:32:22
they're the same sometimes we leave out
00:32:25
the word valued a vector function R of T
00:32:29
is continuous at T equals a if and only
00:32:38
if you guys remember once
00:32:43
[Music]
00:33:07
yes I'm gonna write it differently if
00:33:18
the limit as T approaches a of our R of
00:33:21
T is equal to R they so Alex was saying
00:33:24
as the limit as T approaches a from the
00:33:26
left and the right are the same that
00:33:28
means that the limit exists at that
00:33:30
point so that's the other way of writing
00:33:32
it okay looking at example six is R of T
00:33:39
continuous at 0 so as the is the limit
00:33:47
as T approaches 0 of R of T the same as
00:33:49
R of 0 yeah right we just plugged in 0
00:33:52
for all 3 functions so this example is
00:33:56
continuous at T equals 0
00:33:57
example 7 are we continuous at T equals
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0 no no and that's because of the
00:34:03
l'hopital's rule that we had to do
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questions on vector valued functions