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in this lab we will be studying a
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chemical reaction at equilibrium between
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two complex ion formations of
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cobalt because they form complex ions
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with water and or chloride ions very
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favorably we can see which side of the
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reaction is favored by the color changes
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due to Crystal field Theory which is not
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part of this um lab but we're going to
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be studying later's PR ible and noticing
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at equilibrium if a stress is made and
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let's say a stress is made that forces
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the reaction to go thermodynamically to
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the right we should be able to see a
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nice blue color because the reactants
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get used up and will make more products
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which will be of course that complex
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with the chloride iion as chloride with
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that ligan and of course back at
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equilibrium if we do something that
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favors the reverse um reaction where
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we're going to make more
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of the um Red by using up the reactants
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and we will make more of the Cobalt
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complex that has the water surrounding
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it as the ligan which will be red we can
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observe these shifts in equilibrium so
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let's get
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started so just to show you uh this is
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the color or Baseline colors of the
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Cobalt complex with water and this is
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the color nice blue color of the Cobalt
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complex uh with the chloride ion so
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clearly you can see who's favored and by
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looking at these colors and this is I
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believe a purple color although I have
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difficult time with colors of the
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equilibrium mixture of both all right so
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we're going to put out some test tubes
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here and we're going to follow our
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procedure as follows so here's our four
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test
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tubes and again right now we see the
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pink color so all these test tubes
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currently have a lot more of the
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reactants and products as by the uh pink
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color favoring the Copp complex with
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water so we're going to Vin our first
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test and we're going to just uh add some
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hydrochloric acid into the first test
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tube and doing so we see that
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thermodynamically there is a shift from
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this
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reaction going to the side with the blue
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compound so now we're making a lot more
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cobalt chloride complex the complex that
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is blue
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okay and and very clearly you should be
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able to figure out in your lab who is
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being used up and who's being
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increased all right so in test tube two
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we're going to add some calcium
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chloride and we'll add some more and we
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should be looking at the bottom of the
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test
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tube and the calcium chloride is going
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to dissociate into its ion that's
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important you understand into the
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calcium plus two and the chloride
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negative ions all right calcium is a
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salt all right and as I probably bring
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this closer to us we can see that the
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bottom of the test tube show shows a
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favored thermodynamic pathway meaning we
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see a shift toward the blue side we are
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making a lot more of that Cobalt ion
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complex with the chloride
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ion so clearly you are now shifting one
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way now of course there's not enough
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chloride ions to make full test tube go
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but right where the salt is you can
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clearly see there is some shift that
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favors the formation of the blue complex
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and you should be able to know which
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side was shifting and in your lab or
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which reactants and products are going
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up or going down because of that all
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right so that's one and two test now
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we're going to grab test two number one
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again and we're going to do another test
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here
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at some
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point all right so here comes test tube
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one again which we can see is clearly
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favored all right with the blue compound
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all right and uh now we're going to add
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some
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water all right so now adding some
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Poland Spring water and again this is
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not a uh uh they didn't pay us any money
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to do this but we're going to add some
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water and by adding water you can see
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definitely a shift toward the pink uh
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Cobalt complex and that pink Cobalt
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complex um is on the reactant side so
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again you should be able to figure out
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where the reaction is Shifting to by uh
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whether we making a pink or blue complex
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here all right and again these colors
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are due to Crystal field Theory where
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we're drawing in the lians okay into the
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D's orbitals and causing the D's to
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split pretty cool stuff to go through so
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test tube three here okay we're going to
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add hydrochloric acid which we've done
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already before and we're going to see a
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shift um to that favors um the cobalt
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chloride complex and you should know
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what that shift does and now part of the
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same test now is we're going to add some
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silver
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nitrate notice the silver nitrate bottle
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when it comes into play here has a is a
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um dark bottle that prevents uh light
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from getting in too much cuz the silver
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iron are affected by the Light any case
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you see me adding some silver nitrate
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and clearly I see some solid developing
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as we like to call a precipitate and
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that
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precipitate is building up as I add more
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silver nitrate and I also see a color
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change here okay as I keep adding more
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silver
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nitrate I see it going from this blue
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complex back to the pink side so I
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definitely see a pink color developing
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here as we add some silver nitrate so
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probably going to bring this up to you
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and see up close and personal what this
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looks
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like and there she is and you can see
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the solid on the bottom the solid
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definitely has a white color okay but
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that's not what's affecting the color
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this definitely went pink showing us a
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definite shift in equilibrium to the um
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Cobalt complex that has a pink color and
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you should make the appropriate markings
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in your
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lamp something about making this
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precipitate cause the shift to favor the
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formation of the um reactants the
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original reactants something to think
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about there what did we do there that
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caused that reaction to shift to the uh
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side that produced the pink complex
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silver nitrate H we should know about
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the uh solubility PR uh rules of
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solubility and what the silver ion must
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have done okay so our final test now is
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to put our test Tu 4 which is favoring
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the pink side and I'm bringing a thermo
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um an infrared thermometer to show you
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that the um room or the board behind you
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is 25.5 de C and the and the water I'm
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bringing here is 76° C so I'm going to
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use a hot bath and in this test we're
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going to put the test tube four in the
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hot bath and we're going to see what
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kind of color change will happen now
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we're changing the temperature here so
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we're actually going to shift not so
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much the equilibrium in truth we're
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actually changing the equilibrium
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position to favor one side or the other
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by adding heat okay we are definitely
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Shifting the equilibrium to a new
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position that's favoring if you can see
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the blue Co cobalt chloride complex all
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right and that tells you something about
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where
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the heat is you know something about L
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sher's principle you increase the
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temperature the reaction is going to
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shift to always do the opposite it's
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response is opposite so looks like it's
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shifting in response increasing the
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temperature which means it's trying to
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probably relieve that temperature and
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this should tell you where the heat is
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in this reaction okay is the heat go on
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the reactant side or the product side
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one of the questions in the lab okay is
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to find out whether the board reaction
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is endo and EXO and right here these
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tests are telling you all right so in my
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second test I'm going to add a cold
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water bath and this test should also
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support my understanding uh so here I
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have my U infrared thermometer I get
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about 9° of my ice bath here and I put
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my my warm solution back into the ice
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bath and we can probably guess what's
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going to happen here and lowering the
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temperature the reaction's going to
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shift to do the opposite probably to to
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um increase the temperature so it's
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going to
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favor
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whatever shift of equilibrium that
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favors um the increase in temperature or
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the exothermic way you should know
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decrease in the temperature is the
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stress the reaction is going to changes
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equilibrium to to do the opposite and
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that hint of what's Happening Here
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should tell you from the ice bath test
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and the um hot bath test where the heat
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goes in the reaction side is the forward
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reaction EXO or is the forward reaction
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Endo all right and we can clearly see
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that the cold water bath made uh and
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shifted the equilibrium to favor the red
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complex all right and that's essentially
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this lab from these uh tests independent
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tests you should have be able to figure
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out where the shifts have occurred and
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who's increasing and decreasing and
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definitely whether the forward reaction
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is endo or EXO thermic all the players
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involved are taking their bows here I
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guess I left the water out hope this
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helped
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