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hello everyone and welcome to this video
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lecture on inverse trigonometric
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functions now this video is specifically
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pitched at my students at the University
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of South Florida we were working on
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inverse trig functions this past week
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which would be section 4.6 in our notes
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and we got some of it done but not all
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of it so I'm making this video as a
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supplementary lecture to make sure we
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get through all the information and that
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you are all prepared for upcoming exams
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now if you happen to be a past by
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somebody who saw the video and thought
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I'd like to learn more about inverse
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trick functions don't worry we are going
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to be providing enough background
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information that this video should act
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like a standalone lecture and as long as
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you follow along with me you take notes
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you actually try to work through the
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examples you should walk away with a
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decent understanding of what's going on
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however from what I've said there are
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some things that should be known upfront
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first of all I must really like you USF
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students because I think I've reach done
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this video about 73 billion times that's
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the nature of recording videos that's
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just how it is and this time around I
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think I'm probably going to record it
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and post it warts and all so if you hear
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me say something especially funny you
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know why the second thing you should
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know is since this is going to be kind
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of like a standalone video I am going to
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put in some background information
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however because this is going to be
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primarily supplementary lecture material
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for my students what that means is the
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background material is going to be gone
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through pretty quickly for example I
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have some reminders on this page and I
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am going to go through those reminders
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however they're going to be pretty fast
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the next couple of pages are going to
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have some reminders and some formulas
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that they should already have seen and
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should already know and we're just going
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to pass through them swiftly so we can
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move to the examples which are going to
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be our primary objective with that said
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make sure that you have something to
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write with next to you make sure that
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you have your notes or a good textbook
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or that you are very comfortable drawing
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the original Sixt trig functions and
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let's go ahead and
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begin whenever I start talking about
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inverse functions of any kind I like to
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throw this diagram up on the screen it
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does not actually serve as any kind of
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definition but it is a nice cartoon that
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kind of helps to encapsulate a lot of
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information and I'm going to go through
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that information quickly now so if you
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have a function like the one we've shown
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here f which has an inverse which we
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would call F inverse which is what we've
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written here when we write f with
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negative one like an exponent it does
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not mean a reciprocal then what should
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happen is we should find that F takes
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inputs X in a set a to outputs Y in a
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set B and F inverse should do exactly
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the opposite if you want to think of
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these using real world examples one that
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is near and dear to my heart is the
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example of crimes and detectives don't
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ask me why that is what comes to mind
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but it fits very nicely you see X the
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input in that case would be kind of like
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the culprit who is going to commit the
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crime the opportunity to commit the
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crime the tools all the things that go
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into actually doing the crime before
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it's done the function f takes all of
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those pieces parts and actually commits
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the crime and why is the result of the
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crime the detective then is played by F
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inverse and it starts at the crime
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itself what has happened what the clues
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are surrounding the crime and attempts
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to deduce from that information who the
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culprit was what the means motive and
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opportunity were Etc that is the
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relationship between a function and its
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inverse as pictured here from this
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diagram then we have several things that
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we should note down they are shown here
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but we need to say them a little bit
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more carefully the first concerns domain
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range the function f has a domain of a
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and a range of B meaning that all the
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inputs for f belong to the set a and all
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the outputs for f belong to the set b as
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you can see here from our diagram our
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diagram also says now when you look at
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it that the domain for f inverse ought
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to be B the things that we plug into F
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inverse all sit in the set B and the
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things that come out of f inverse all
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belong to the set a so that means the
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range for f inverses a which you'll
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notice is the reverse of what we had
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before that's very natural that's
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exactly how inverses and functions
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work another thing that we can learn
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from looking at the diagram but which we
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have to be careful about is some
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equation properties of these functions
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the first one on the left hand side says
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if I feed an output y to F inverse I'm
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going to get an input for my function f
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if I feed that input to F the result is
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going to be y again just like what I
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plugged into F inverse similarly if I
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plug the input X into F I'm going to get
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an output if I feed that output to F
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inverse I should come back to the
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original input
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X now those two equations really mean
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follow the arrows in my diagram if I
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start at y feed it to F inverse and then
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feed that to F I come back to Y again
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exactly like my equation said if I start
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at X feed it to F and then feed that to
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F inverse I come back to X again so
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we've kind of already got it in the
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picture another good reason to have the
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picture hanging around it says the same
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thing but it looks nicer the other
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equations we're interested in on the
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right hand side are what we would call
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equivalent equations meaning they mean
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exactly the same thing f ofx = y and F
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inverse of yal X are exactly the same
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information and we've noted that with
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this double-ended arrow in between them
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if you want to think of it this way they
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are just different perspectives on the
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same information if I'm talking about
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myself I might call myself Dr forest or
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Zach if somebody else was talking about
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me they might say he is Zach or they
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might say he is Dr Forest same
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information but from a different
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perspective and that's what these
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equations say whether you come from the
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perspective of f or the perspective of f
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inverse this is the same
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information the final thing that we need
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to include is a function f which has an
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inverse must pass the horizontal line
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test now what does that look
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like well if I take a couple of basic
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functions you can see one of them is a
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straight line and one of them is a
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parabola a function that passes the
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horizontal line test should see the
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following if I draw any horizontal
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line it should do one of two things
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either it should fail to intersect the
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graph of my function entirely or like
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you see in my picture here it should
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intersect the graph of my function
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precisely
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once this must happen for every single
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horizontal line I
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draw as you can see with a straight line
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this works every horizontal line I draw
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passes through my line precisely once
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and that's okay if you look at my
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Parabola though we're not so lucky yes
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there are some horizontal lines that
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don't pass through the graph of my
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Parabola yes there is a horizontal line
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it's the x-axis that only touches my
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parab Parabola
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once
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however because I can draw a horizontal
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line just one that does not intersect
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once it intersects
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twice that means that my Parabola does
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not pass the horizontal line test from
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that from this horizontal line test you
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can usually learn some
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information as we said an inverse a
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function that has an inverse must be
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able to pass the horizontal line test
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the flip side of that is is if a
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function does not pass the horizontal
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line test then it should not have an
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inverse now you may be thinking to
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yourselves now hang on the graphs of
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trig functions should not pass the
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horizontal line test trig functions are
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periodic they repeat themselves over and
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over and over again so if I draw a
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horizontal line I should intersect more
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than one point on any trig function and
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you're right this is 100% true but
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luckily there is a way to get around
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that and the way to get around that
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appears on the next
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page now before we get started I will
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admit this is a very dense page of
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information you can see that from just
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this little excerpt that's on the screen
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right now and as I mentioned we are
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covering six functions six inverse
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functions that we need to be worried
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about but there's a couple things I
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would say to that first of all any time
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that you feel like you need a break
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pause the video and take a break walk
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away for a few minutes stretch your legs
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go to the bathroom have a snack come
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back when you're ready it'll still be
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here the second thing I'll will say is
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although I am going to pay some
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attention to sign and there are a couple
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of occasions where I may have to draw a
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graph potentially I am going to for the
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most part introduce the critical
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information for sign and from that point
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onward because as you can already see
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this information kind of repeats as you
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go through I'm going to indicate where
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things are a little bit different or
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explain why they are different so it
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won't quite as dense as it looks here
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this is mostly for completeness of notes
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so saying let's look at sign now as we
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said sign does not pass the horizontal
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line test normally however if I restrict
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sign to a subdomain meaning instead of
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working with all of the possible inputs
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I only work with the inputs between pi/
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2 and Pi / 2 which for those of you who
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are visually minded if I draw the unit
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circle means I am talking about only
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those
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angles in the right hand half of the
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unit circle since we know that < /2 is
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Down Below on the Y AIS and Pi / 2 is up
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above on the Y
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AIS then we have a one: one function
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once we have a one: one function for
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sign on the subdomain we can Define arc
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sign an inverse the inverse then has to
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satisfy a couple of equations which
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shouldn't be surprising after our
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previous p page and they are s of sin
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inverse of a number a should just give
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us a back again and sin inverse of s of
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an angle Theta should give us the angle
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Theta back again but there are some
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caveats a really here is the output of
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sign it is one of the outputs that s
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gives us because remember when we're
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working with a function and an inverse
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we're going back and forth between the
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inputs and the outputs that means that a
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has to fall into the interval from -1 to
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1 and that is also the domain for arc
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sign or inverse sign however you prefer
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to say it Theta is going to have to be
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between piun over 2 and pi/ 2 because
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that's the Restriction we had to make in
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order to get this Ark sign to begin with
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and Pi / 2 to Pi / 2 is the outputs for
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our Ark sign meaning it is the
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range similarly if we move on to cosine
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by restricting cosine to 0 to Pi which
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in our picture corresponds to the upper
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half of the unit circle up
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top it turns out that we can make Arc
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cosine the inverse cosine and it
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satisfies similar equations to what we
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saw up above the big difference being
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that while a still needs to be between 1
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and 1 so once again the domain for AR
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cosine is -1 to 1 the range now is from
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0 to Pi
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moving to tangent I think it's helpful
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to see a a basic sketch of what tangent
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looks
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like so I have sketched one cycle of
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behavior for tangent you'll notice I've
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included its vertical ASM tootes which
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we know for probably the easiest to work
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with full cycle of tangent happen to be
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at piun / 2 and Pi
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over2 this explains why when we move to
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the subdomain for tangent the one we
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have to restrict it to it is from piun /
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2 to piun / 2 kind of like with s but we
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have to exclude the end points because
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those end points are ASM tootes so we
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can't include them once again once we
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make the Restriction we can define arct
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tangent the inverse function and it
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satisfies the equations but
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now the number a can be any real number
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it can be anything from negative to
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positive Infinity specifically because
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tangent goes from negative to posit of
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infinity and Theta must be in the
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restricted domain from piun 2 to piun /
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2 these first three are all pretty
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straightforward the next couple are
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cosecant and secant now in my classes we
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haven't talked about cosecant and secant
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except in passing so I think the most
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useful thing I can do to begin with is
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just provide you with a basic sketch of
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how I get their pictures
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to do this I begin with graphs of s and
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cosine I've only drawn a little bit of
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them because I'm only going to work with
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a relatively small amount of them and I
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make an observation cosecant is the
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reciprocal of s as long as s is not
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equal to zero that means whenever sign
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is not equal to zero say for example
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when s is equal to 1 cosecant is found
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by taking one and dividing it by the
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value of s so when s is equal to 1
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cosecant is is also equal to 1 it is 1 /
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1 when s is equal to -1 cosecant is also
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equal to 1 because you will take one and
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divide it by the value of s 1
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over1 anytime that s is zero well then
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we're going to have to put in a vertical
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ASM
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toote from here we draw this strange
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looking function wherever it is above
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the xais it cups
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upward whenever it is below the xais it
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cups downward like
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so similarly if we do this for
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secant we can label the points where
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secant is equal to one and negative 1 we
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can label where the vertical ASM toote
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should be and once again we get these
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funny little cupping shapes above the
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x-axis they go up below the xaxis they
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go down
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and it's because of these funny shapes
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that we wind up getting the restrictions
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that we do so you'll notice we have to
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restrict cosecant to the subdomain from
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piun / 2 to Pi / 2 which is a lot like s
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except we can't include zero because
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zero is an ASM toote in our picture
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otherwise it should be the same
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subdomain once we do that we get the
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same basic equations like what we would
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expect the difference is first of all we
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have to restrict Theta to that weird
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little uh subdomain from piun 2 to Pi /
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2 but don't include zero second of all
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we have to say that a is from negative
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Infinity to - 1 or it is from 1 to
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infinity and that comes directly from
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this cupping Behavior you'll notice that
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we never find secant between negative 1
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and 1 it is either negative 1 and Below
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or positive 1 and above and that
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explains why a is in this funny looking
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interval here once again we are looking
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at the Domain and the range for our
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inverse function similarly when working
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with secant we find out that we really
00:16:05
want to mimic the behavior of cosine
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it's just that if we go from 0 to Pi
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we're going to wind up with this
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vertical ASM toote in the middle so we
00:16:13
go from 0 to Pi and remove the vertical
00:16:16
asmp toote at Pi / 2 after that we wind
00:16:19
up with the standard looking equations
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we get the domain of arc secant which is
00:16:24
again from negative Infinity to 1 and
00:16:27
from 1 to infinity and and we restrict
00:16:30
Theta from 0 to Pi excluding the ASM
00:16:33
toote Pi /
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2 after these two functions I would say
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that coent is relatively quite easy once
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again let me go ahead and sketch
00:16:47
coent coent has a very similar shape to
00:16:50
tangent the difference being tangent
00:16:52
increases over its cycle whereas Cent
00:16:55
clearly decreases Cent has an AS toote
00:16:59
at zero and another ASM toote at pi and
00:17:02
this explains the subdomain we're going
00:17:04
through a full cycle of behavior from 0
00:17:07
to Pi but not including the asmp tootes
00:17:10
once we do that restriction we are able
00:17:12
to put down these predictable equations
00:17:16
once again cotangent goes down to
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negative Infinity up to positive
00:17:19
Infinity so a must belong to negative
00:17:22
Infinity to
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infinity and Theta must belong to 0 to
00:17:27
Pi and these are once again let me go
00:17:29
ahead and state it over and over again
00:17:31
these are the domain and the range of
00:17:33
Arc cotangent we're going to need these
00:17:36
domains and ranges and this is why I've
00:17:38
labeled them this way now at this point
00:17:41
we are almost ready to do examples which
00:17:44
is of course the thing we want to do
00:17:46
most but before we do that we have one
00:17:48
more page of information we need to go
00:17:50
over and it's just to prepare you for
00:17:52
the
00:17:55
examples I have some major equations for
00:17:58
each of the six inverse or Arc trig
00:18:01
functions now at this point I would say
00:18:03
just pause the video and write them all
00:18:05
down so you can refer to them later I
00:18:07
will also say to you these are not the
00:18:09
only ones there are some others for
00:18:12
example for USF students in our textbook
00:18:14
you will quickly find that there are
00:18:15
more equations you'll notice that I have
00:18:18
green equations that talk about what Ark
00:18:21
sign for example does with negative a
00:18:23
but I haven't done that for Arc cosecant
00:18:26
there is an equation for Arc cosecant
00:18:28
that looks kind of similar however I
00:18:31
have not included it the reason for that
00:18:33
is actually pretty simple when I'm
00:18:36
working with these inverse trig
00:18:37
functions these are the ones that I use
00:18:40
predominantly the ones in
00:18:42
Black sometimes I will use the green
00:18:44
ones mostly the green ones will be taken
00:18:46
care of by sketches as I'll show you
00:18:48
when we go through the examples but I
00:18:50
include them both because I can match up
00:18:54
these equations with the sketches that I
00:18:56
draw later on when we get to the
00:18:57
examples and also because sometimes the
00:19:00
homework software will ask you to use
00:19:02
one of these equations so it's important
00:19:04
to have them in front of you and to
00:19:06
think about them and know what they
00:19:09
are now I don't want to beat a dead
00:19:11
horse with these uh equations that I've
00:19:14
written up here I am 100% confident that
00:19:16
all of you can read the equations that
00:19:18
I've written so what I'm going to do is
00:19:21
I'm simply going to summarize the
00:19:22
information that you see here once again
00:19:25
kind of like we talked about on the
00:19:26
first page whenever I have a function
00:19:29
that has an inverse even if I had to do
00:19:30
a little bit of restricting in order to
00:19:32
get to this point I can write
00:19:35
information about the functions two
00:19:37
different ways I can either say the
00:19:39
function of an input is equal to an
00:19:41
output or I can say the inverse function
00:19:44
of the output is equal to the input the
00:19:46
Only Rule here is a must be in the
00:19:53
domain so if you go back to the previous
00:19:56
page and look through that whole list of
00:19:58
function and definitions there whatever
00:20:00
the domain is for your particular
00:20:02
inverse trig function a must be in that
00:20:05
domain
00:20:06
andeta must be in the
00:20:10
range if that doesn't happen these
00:20:13
equations that I've written here don't
00:20:14
make any sense anymore and they can't be
00:20:16
used so you have to keep that in mind
00:20:18
when you're working on these things as
00:20:21
long as we have that information here I
00:20:23
think that we are ready to do our very
00:20:24
first
00:20:27
example now for those of you students uh
00:20:29
at USF you will notice that I have done
00:20:32
probably a whole bunch of problems at
00:20:34
this point that look like the one I've
00:20:35
done here calculating arc sign for
00:20:38
various uh values here I still want to
00:20:43
include it in our notes because I feel
00:20:44
like it is important to do these
00:20:46
examples over and over again until it
00:20:48
clicks also we've not used these
00:20:50
particular values so this is good
00:20:53
practice I'm going to go ahead and start
00:20:55
with the Positive value for a so I am
00:20:58
going to start
00:20:59
with sin inverse or S of < tk3 /
00:21:06
2 and the very first thing I'm going to
00:21:08
do we've mentioned this in class is I'm
00:21:11
going to double check that this value
00:21:13
actually belongs to the to the domain
00:21:16
now I happen to remember the domain for
00:21:18
AR sign go back if you don't but arc
00:21:22
sign has a domain of -1 to 1 and a
00:21:25
little bit of calculation if you have to
00:21:28
put it into to a calculator will show
00:21:30
you that < tk3 over2 belongs to that
00:21:33
domain so it is okay to talk about AR
00:21:36
sign of < tk3 over2 and we should get an
00:21:40
answer for now I'm going to put Theta in
00:21:44
the answers Place Theta is just a dummy
00:21:46
variable meaning not that I'm a dummy or
00:21:48
at least I hope I'm not but rather that
00:21:50
I'm filling in the space because now
00:21:53
that I've written the equation AR sign
00:21:55
of a number equals Theta which is kind
00:21:57
of like the right hand side of this
00:21:59
major equation up here I can now write
00:22:02
the other
00:22:05
perspective the other perspective would
00:22:07
be if I take s of theta I should be
00:22:10
getting < tk3
00:22:15
over2 so what we're looking for now just
00:22:17
to make sure you remember is an angle
00:22:20
Theta the angle Theta has to be in the
00:22:22
range of arc sign again I'll let you go
00:22:25
back and check but the range for arc
00:22:27
sign should be the right hand half of
00:22:30
the unit circle from negative pi over2
00:22:32
to positive Pi / 2 so are there any
00:22:35
angles between negative pi over2 and Pi
00:22:37
/ 2 that give us < tk3 over2 when I plug
00:22:40
them into sign absolutely if you
00:22:44
recall s of pi over 3 which in other
00:22:48
words means s of
00:22:50
60° is equal to < tk3
00:22:54
over2 in fact if you look through the
00:22:57
right hand half of the unit circle
00:22:59
meaning quadrant 1 and Quadrant 4 you're
00:23:02
going to quickly find out that that
00:23:03
doesn't happen anywhere else pi over 3
00:23:06
is the only angle for which s gives us <
00:23:09
tk3 over2 so with this in mind there's
00:23:12
only one possible answer for Theta as
00:23:15
long as Theta is following the rules as
00:23:17
long as Theta belongs to the range of my
00:23:19
arc sign Theta must be pi over
00:23:25
3 Let's scoot down a little bit I'm
00:23:27
going to change colors to Blue and we're
00:23:30
going to do this again but now we're
00:23:32
going to do it for the negative value so
00:23:34
we will say we're taking arine of < tk3
00:23:43
over2 once again < tk3 over2 is in the
00:23:47
domain of Ark sign it is between 1 and 1
00:23:50
so I'm going to put a dummy variable
00:23:53
once I have written an equation I'm
00:23:55
going to write the other perspective on
00:23:57
that equation that if I take sign of
00:24:00
whatever this angle is I must be getting
00:24:02
out of
00:24:03
it < tk3
00:24:06
over2 and I'm going to stop and think
00:24:08
about this one for this one I really
00:24:10
need to have a diagram so I'm just going
00:24:12
to really quickly sketch
00:24:14
one now last time when we were drawing
00:24:18
things we wound up with a an answer an
00:24:21
angle that was in the first quadrant you
00:24:24
should go and check this for yourself
00:24:26
but Pi 3 is definitely in quadrant 1 and
00:24:30
that makes sense because in quadrant 1
00:24:32
every single one of the trig functions
00:24:33
is positive however this time around
00:24:36
we're getting negative
00:24:38
answers since we are stuck with the
00:24:40
right hand side of the unit circle
00:24:42
between Pi / 2 and positive Pi / 2
00:24:47
there's only one place where this angle
00:24:49
can live if it is going to make any
00:24:51
sense and that angle is here in Quadrant
00:24:55
4 specifically we must get to it by
00:24:58
rotating the wrong way into Quadrant
00:25:02
4 H now what angle could do
00:25:07
that oh now wait a second if I rotate to
00:25:11
an angle like this in Quadrant
00:25:13
4 notice s of piun / 3 is postive < tk3
00:25:18
/
00:25:19
2 and what that's implying to us is
00:25:22
because of the way s works because s is
00:25:25
an odd function and it goes positive
00:25:28
when I go go this way but negative when
00:25:29
I go this way if I take S ofk
00:25:36
3 I must get < tk3
00:25:43
over2 because of that and because kind
00:25:45
of like last time if you start checking
00:25:47
around you find out that there is no
00:25:50
other angle between piun / 2 and pi over
00:25:52
2 that gives me this result it must be
00:25:55
that the answer for this particular
00:25:57
equation is that Theta must beunk over 3
00:26:01
or in other words Ark sign of < tk3 /2
00:26:05
is equal to pi over
00:26:08
3 now I want you to take a look at these
00:26:10
answers last time when I took Ark sign
00:26:13
of ro3 over2 I got pi over 3 this time
00:26:17
when I took Ark sign of NE < tk3 over2 I
00:26:21
got netive piun
00:26:23
over3 that is exactly what this green
00:26:25
equation says here if I take Ark of the
00:26:29
negative of a then the result must be
00:26:32
the negative of whatever AR sign of a
00:26:34
gave
00:26:36
me in other words we've just recreated
00:26:39
the green equation for Ark sign we've
00:26:41
just done it using diagrams and using
00:26:43
our work here that should not be too
00:26:47
surprising okay let's go ahead and do
00:26:49
another
00:26:52
example in fact we're going to go ahead
00:26:55
and do the same exercise again but this
00:26:57
time we're going to work with Arc cosine
00:26:59
instead of Co instead of AR
00:27:02
s now I'm going to go ahead and show the
00:27:05
steps again a little bit faster but
00:27:07
after we do this example I'm going to
00:27:09
speed things up a bit so be prepared
00:27:12
make sure you're taking notes
00:27:14
here once again I'm taking Arc cosine
00:27:18
I'm taking it of let's say the positive
00:27:21
first I'm checking to make sure that Roo
00:27:23
tk3 over2 belongs to The Domain it does
00:27:26
we happen to know the domain for Arc
00:27:28
cosine and AR sign are identical and
00:27:30
we're setting up our dummy variable so
00:27:32
that we can rewrite our information from
00:27:35
the other perspective that is for this
00:27:39
first equation to be true it must also
00:27:41
be true that cosine of the angle Theta
00:27:43
whatever Theta is must be giving us <
00:27:45
tk3
00:27:47
over2 this is going to give us a
00:27:49
different answer than last time however
00:27:52
if you start looking through the range
00:27:55
for Arc cosine which I will remind you
00:27:57
is the upper half of the unit circle
00:28:00
first of all because we have a positive
00:28:02
answer here we must be talking about an
00:28:04
angle in quadrant one because quadrant 2
00:28:07
is where cosine is negative or I should
00:28:09
say one of the places where cosine is
00:28:11
negative second of all I happen to know
00:28:15
from experience that 30° which is to say
00:28:20
pi/
00:28:21
6 is an angle for which we get < tk3
00:28:24
over2 when we plug it into cosine and in
00:28:28
fact it is the only angle in the upper
00:28:31
half of the circle that does that so it
00:28:33
must follow that Theta is equal to pi/ 6
00:28:40
30° giving myself a little bit of room
00:28:44
if I do the same thing again but this
00:28:46
time with my AR cosine of negative < tk3
00:28:52
over2 I check my domain considerations
00:28:55
they're good I write an equation with a
00:28:58
dummy variable so I can write my other
00:29:06
perspective I note looking at this
00:29:09
second equation that cosine of theta is
00:29:11
giving me a negative and since we are
00:29:13
restricted to the upper half of the unit
00:29:15
circle which is quadrants 1 and
00:29:17
two this implies to me that Theta must
00:29:20
belong to quadrant 2 so the question
00:29:22
then is what is an angle in quadrant 2
00:29:25
that does what we
00:29:26
want well last time when we were working
00:29:29
with Ark sign I didn't say the word
00:29:34
reference angle but I'm going to say it
00:29:36
now because here's what I
00:29:42
notice if I draw an angle in quadrant
00:29:48
2 this will be my Theta right
00:29:52
here I will get negative as I want it if
00:29:56
I want to make sure that Co of theta
00:29:58
gives
00:29:59
mek3 /2 one thing that I could appeal to
00:30:04
is reference
00:30:06
angles I already know that cine of piun
00:30:09
/ 6 gives me positive < tk3 over2 so if
00:30:12
I ensure that the reference angle for
00:30:15
Theta is pi/ 6 then cosine of theta
00:30:20
should basically be the same as pi over
00:30:22
6 except because it is in quadrant 2 it
00:30:27
will be negative so here's a question
00:30:29
what angle in quadrant 2 has a reference
00:30:32
angle of Pi / 6 well there's actually a
00:30:36
pretty easy way to set that up and
00:30:37
figure that
00:30:40
out since we are drawing an
00:30:44
angle Theta here in quadrant 2 and since
00:30:47
the reference angle that we've indicated
00:30:49
is between Theta and Pi we could always
00:30:52
set up an equation that looks like this
00:30:54
when I take pi and I subtract Theta I
00:30:58
should get Pi / 6 the reference angle if
00:31:01
we solve this for Theta we wind up
00:31:05
finding that Theta must be equal to piun
00:31:09
- < / 6 and if you run the calculations
00:31:12
on that that means Theta must be equal
00:31:15
to 5 pi/ 6 so coming back up to my
00:31:20
work I write down well cine of 5 piun /
00:31:26
6 is equal to < tk3 / 2 as desired so we
00:31:32
must find that Theta is equal to 5 piun
00:31:37
over 6 and that completes the
00:31:39
exercise now last time when we got to
00:31:42
this point we compared our answers last
00:31:44
time we found R cosine ofun 33/2 was
00:31:47
piun / 6 this time we found R cosine of
00:31:51
negative < tk3 over2 was 5 pi over
00:31:54
6 really the comparison though is
00:31:57
between the previous answer in red and
00:31:59
what we wrote down here below our sketch
00:32:02
you notice that when we figured out what
00:32:04
Theta what our answer would be we had to
00:32:07
take pi and subtract pi/ 6 or in other
00:32:10
words we had to take pi and subtract our
00:32:12
old answer well if we go back up again
00:32:16
you'll notice that the companion
00:32:17
equation in green for Arc cosine is if I
00:32:20
want to do AR cosign of the negative of
00:32:23
some number a I can find it by taking pi
00:32:26
and subtracting R Co of a for us that
00:32:29
means R cosine of3 /2 is the same thing
00:32:33
as Pi minus r cosine of POS < tk3 over2
00:32:37
and you'll notice that we've recovered
00:32:39
this property as
00:32:40
well it's one of the reasons why we
00:32:42
really don't need those properties even
00:32:44
though it's good to talk about them we
00:32:46
can reproduce them even without having
00:32:48
to have the formulas in front of
00:32:52
us let's do an example for arc tangent
00:32:56
you'll notice in this one I've only
00:32:57
given one value that I want to check I
00:33:00
want to make sure we speed things up I
00:33:02
think by now you should be getting the
00:33:04
gist of how we do these things so in
00:33:06
fact as I promised I'm going to do this
00:33:08
kind of quickly pause the video and try
00:33:10
to see if you can fill in the gaps that
00:33:12
I'm about to fill in and see where you
00:33:17
are okay basic stuff out of the way we
00:33:20
know that the domain for arc tangent is
00:33:23
all real numbers so there's really
00:33:25
nothing to check there if we write the
00:33:27
dummy equation and then write the other
00:33:29
perspective we find that tangent of
00:33:31
should be equal
00:33:32
tok3 and once again we're dealing with a
00:33:36
situation where we must have an angle in
00:33:39
a different quadrant than quadrant one
00:33:41
we know that tangent is going to be
00:33:44
restricted to an arc tangent has a range
00:33:46
of negative piun over 2 to positive piun
00:33:49
/ 2 and clearly if we were in quadrant
00:33:51
one we would have a positive result
00:33:54
since we're getting a negative result
00:33:56
this must mean that we are going to be
00:33:58
dealing with something in Quadrant 4
00:34:00
going in the negative
00:34:03
Direction sketching out a picture as I'm
00:34:06
want to do when I need some
00:34:09
ideas I must be talking about an angle
00:34:13
somewhere down here like so going this
00:34:21
way now I have to think through some of
00:34:24
my reference angles here I need to think
00:34:26
through the basic angles like the
00:34:28
quadrantal angles those would be big
00:34:30
ones for me and then the angles pi/ 6 30
00:34:33
uh 30° pi over 4 45° and pi over 3 which
00:34:38
is
00:34:39
60° and as I think through those I have
00:34:42
a
00:34:43
recollection I
00:34:47
recall that the angle pi over 3 in other
00:34:51
words 60° has an x coordinate of 12 and
00:34:55
a y coordinate of < tk3 two on the unit
00:35:00
circle since tangent is given by the y
00:35:04
coordinate divided by the x
00:35:07
coordinate this tells me with a little
00:35:09
bit of simple calculation that tangent
00:35:11
of pi over 3 must be equal or excuse me
00:35:15
tangent of pi over 3 must be equal to
00:35:17
positive < tk3 which is almost what we
00:35:21
want here's another observation if you
00:35:24
notice if I were to make this angle in
00:35:27
red the one I'm trying to figure
00:35:30
outk
00:35:32
3 notice that that would mean that these
00:35:35
two angles the pi over 3 and the
00:35:37
negative pi over 3 should be direct
00:35:39
reflections of one another across the x
00:35:43
axis whenever that happens we know that
00:35:47
the y coordinate would change so we
00:35:49
would have still2 for the x coordinate
00:35:52
but now a NE < tk3 over2 for the
00:35:56
y-coordinate
00:35:58
since the y-coordinate is negative and
00:36:01
the x coordinate is positive this
00:36:03
implies that tangent of pi over 3 will
00:36:05
be a negative number but otherwise it
00:36:07
should give us pretty much the same
00:36:09
answer so in fact what we figured out
00:36:11
from this diagram is tangent of piun
00:36:14
over 3 gives us the value we
00:36:19
want listen to that my dog is
00:36:21
celebrating in the background you go
00:36:25
girl and that must mean that Thea is
00:36:28
equal to negative or excuse me
00:36:32
a no I was right the first time man I
00:36:35
got distracted by the dog what can I say
00:36:38
dogs distract people Theta must be equal
00:36:41
to piun over 3 and there you go we've
00:36:44
got our
00:36:46
example now that we have the basic
00:36:49
examples for Ark sign through arc
00:36:52
tangent I want to do a couple of
00:36:54
problems for the other weird functions
00:37:01
part of this is because they are a
00:37:02
little bit weird but also to show you
00:37:05
the rules that I use for evaluating
00:37:09
them oh she's singing now that's very
00:37:11
sweet all right sing us into the next
00:37:14
problem oh sweet
00:37:16
doggo oky doie we have our next example
00:37:21
calculate Arc secant of two now I'm
00:37:25
going to leave it up to you to double
00:37:27
double check that two falls into the
00:37:30
domain for arant you've got to get used
00:37:32
to doing this for yourself so I'm going
00:37:33
to go ahead and let you do that part I'm
00:37:36
also going to use this time to remind
00:37:40
you once again just like with all the
00:37:42
previous examples we must have another
00:37:45
perspective that we can
00:37:48
write and I guess more accurately what I
00:37:51
really want to do is to take this to
00:37:52
remind you you should be getting used to
00:37:54
writing these yourself I've taken the
00:37:56
liberty of doing it here make sure that
00:37:58
you're writing these yourself now what I
00:38:01
need to do from here is a little bit
00:38:03
different from the last few times I
00:38:05
really don't want to have to work with
00:38:06
secant because secant is a bit weird
00:38:08
being a reciprocal function so instead
00:38:11
I'm going to make an
00:38:13
observation if secant of theta is equal
00:38:15
to 2 because I know that cosine and
00:38:18
secant are reciprocals of one another it
00:38:21
suggests that cosine of theta must be
00:38:24
equal to 12
00:38:28
if we can work with cosine of theta is
00:38:29
equal to 12 well that's a much easier
00:38:32
situation to work with in fact if you
00:38:34
know your basic reference angles pretty
00:38:37
well then you should know which angle to
00:38:39
look
00:38:41
for reaching through my memory here I
00:38:45
recall that
00:38:49
cosine of pi over
00:38:53
3 is equal to 12
00:38:58
I am that good I think it should be
00:39:00
recorded on video but on top of that you
00:39:03
can actually see up above I drew the
00:39:05
angle pi over 3 and look the x
00:39:07
coordinate is 1/ 12 and cosine is the x
00:39:09
coordinate points on the unit circle so
00:39:12
with that information in toe I know that
00:39:15
cosine is of Pi 3 is what I want for
00:39:18
this line since pi over 3 makes cosine
00:39:21
equal to 12 it also makes secant equal
00:39:23
to two and it's the only angle that does
00:39:26
that
00:39:28
in well in the range that we're looking
00:39:32
at which we should go ahead and write
00:39:35
down because I realized I hadn't written
00:39:37
that
00:39:39
down the range that we're looking at
00:39:42
should be the upper half of the unit
00:39:44
circle except for except for the line
00:39:49
where Theta is equal to Pi /
00:39:51
2 so since this is the only angle that's
00:39:55
going to give us a satisfactory answer
00:39:57
it follows at once that our answer to
00:39:59
the problem is that we must be getting
00:40:02
pi over 3 see inverse of 2 must be equal
00:40:05
to pi over
00:40:07
3 we're going to do this again let's go
00:40:09
ahead and do it for
00:40:13
cosecant all right if we're doing this
00:40:15
problem for cosecant we have to do a lot
00:40:17
of the same setup we are going to have
00:40:19
to start out and verify that two does
00:40:22
indeed belong to the domain of cosecant
00:40:24
AR cosecant I should say let's be
00:40:26
precise here here we are also going to
00:40:28
have to write the other perspective
00:40:30
equation and we are going to have to
00:40:32
write out another equation this time
00:40:35
because cosecant is the reciprocal of s
00:40:39
it won't be cosine of theta that we want
00:40:41
to work with but co uh but s of theta so
00:40:44
I'm going to let you go ahead and write
00:40:46
that stuff down I'm going to return with
00:40:48
my answers in just a
00:40:51
moment we're back so you can see how
00:40:54
I've written everything down you see
00:40:56
that we should be finding out that
00:40:58
whatever our answer is if I plug that
00:41:00
angle into sign I should be getting 1/2
00:41:03
and I know that when I'm looking at ARC
00:41:05
cosecant and its answers the result
00:41:07
should be somewhere on the right hand
00:41:09
side of the unit circle excluding the
00:41:12
line where Theta is equal to zero now
00:41:15
once again I've chosen this value two so
00:41:18
I get 1/2 and that's because 1/2 happens
00:41:21
to correspond with one of our common
00:41:22
reference angles
00:41:25
specifically if you do a little bit of
00:41:26
Cal calculation you'll find out that s
00:41:30
ofk / 6 s of 30° is equal to
00:41:35
12 and so the answer we should be
00:41:38
getting for this problem is pi 6
00:41:43
predictably this shows you between these
00:41:45
two examples the basic Theory as it
00:41:47
applies to Arc cosecant Arc secant and
00:41:51
even our cotangent although I will leave
00:41:53
that example for you to try out what you
00:41:56
really need to do is get to the point
00:41:57
where you've written the second
00:41:59
perspective on the same information then
00:42:02
rewrite the equation using the
00:42:03
reciprocal function for secant that's
00:42:06
cosine for cosecant that's s for coent
00:42:10
because of the uh reciprocal identities
00:42:14
you're going to have to go and look
00:42:15
those up in the textbook but because of
00:42:17
the reciprocal identities for cotangent
00:42:19
that will be tangent once you write that
00:42:21
equation you will know what to do from
00:42:24
there this should be enough examples of
00:42:26
this type of problem let's move on to
00:42:28
some more challenging and more
00:42:29
interesting
00:42:32
ones scrolling down just a little bit we
00:42:35
have our next problem we want to
00:42:37
calculate sin inverse of s of pi over 3
00:42:40
this is one of the common types of
00:42:41
problems you're going to run into when
00:42:42
you're doing your homework problems we
00:42:45
have to figure out how to evaluate this
00:42:48
now there is a fast way to do this and
00:42:50
so I'm going to do the fast way because
00:42:52
I think it will help you remember some
00:42:54
important properties but if you remember
00:42:56
I'll just just put this here as a little
00:42:58
reminder to go back to that second page
00:43:00
of notes that we made apparently eons
00:43:04
ago when I take s inverse of s of an
00:43:10
angle Theta the result is going to be
00:43:13
Theta
00:43:16
if Theta is
00:43:18
in the restricted domain well I guess I
00:43:22
should say either in the subdomain for
00:43:24
sign or in the range of Arc sign which
00:43:27
in our case means between PK /
00:43:30
2 and < /
00:43:35
2 we wrote this down on the previous
00:43:37
page when we defined these functions and
00:43:39
it's important here because as I look at
00:43:42
my problem here I realize pi over 3 is
00:43:45
in this interval specifically pi over 3
00:43:48
is a quadrant one angle so it makes
00:43:51
perfect sense that it should be less
00:43:52
than Pi / 2 and it's definitely bigger
00:43:54
thank / 2 with that that said I really
00:43:58
don't need to do any
00:44:00
calculation the answer is just pi over
00:44:03
3 but I would also like to go ahead and
00:44:07
sketch a really quick picture for you
00:44:08
because I think it helps to illustrate
00:44:10
something we're going to need in a
00:44:13
moment all right I have gone ahead and
00:44:15
drawn the angle pi over 3 and I've
00:44:18
included also its terminal point and
00:44:21
here's why I say that remember that
00:44:24
What's Happening Here is we are
00:44:26
basically going through through steps if
00:44:28
we were to follow our diagram like we
00:44:30
did on the first page what would happen
00:44:32
is we would first plug pi over 3 into s
00:44:35
and it would take us to this value here
00:44:39
then what we would do is we would want
00:44:41
to find an angle that gives us this
00:44:43
value when we plug the angle into sign
00:44:46
which must be the angle that goes along
00:44:47
with it here in my drawing now it's kind
00:44:50
of useless here because we have this
00:44:53
nice information sin inverse of sin of
00:44:56
theta equal Theta
00:44:57
specifically because Pi 3 belongs to the
00:45:01
uh the range of Ark sign but in just a
00:45:04
little bit we're going to see problems
00:45:06
where it's not quite so clear-cut so I
00:45:07
want to get used to drawing these
00:45:09
pictures you're going to need them again
00:45:11
in a
00:45:13
moment our next example calculate
00:45:16
tangent of tangent inverse tangent of
00:45:19
arc tangent of pi over 3 now once again
00:45:22
there's something important to recall so
00:45:24
I'll go ahead and put that here
00:45:29
remember from page two when I take
00:45:32
tangent of arc tangent of a we get a
00:45:34
again as long as a belongs to the domain
00:45:39
of arc tangent it's between negative
00:45:41
infinity and infinity now in this
00:45:44
particular case that makes things really
00:45:46
easy again we really don't have much to
00:45:48
worry
00:45:49
about this just says a has to be a real
00:45:52
number well it's pi over 3 a real number
00:45:54
you beta so when I come over here and WR
00:45:57
the answer is pi over 3 the tangent and
00:46:00
the arct tangent undo each other and I'm
00:46:02
simply left with whatever a was that's
00:46:04
all there is to
00:46:06
it but now is when things are going to
00:46:08
get a little bit tricky and this is
00:46:10
where we're going to have to start
00:46:11
paying attention to things because it's
00:46:13
not always this
00:46:16
clean for example check out this problem
00:46:19
right here cosine of cosine inverse of
00:46:23
pi/ 3 calculate if it exists you'll
00:46:27
notice I've put the hint if it exists
00:46:29
here because I'm not going to be leaving
00:46:30
you in suspense for very long and the
00:46:32
answer is it doesn't here's the basic
00:46:35
reason
00:46:38
why recalling from page two that cosine
00:46:42
of Arc coine of a is equal to a if a
00:46:46
belongs to -1 to 1 we now really have to
00:46:50
ask ourselves a question we know the pi
00:46:53
over 3 is a real number but is it in
00:46:55
this interval well actually a quick
00:46:57
estimate will show us it is not it's an
00:47:00
easy one too when looking at the number
00:47:03
pi over 3 I happen to know that Pi is
00:47:06
bigger than three it's
00:47:09
3.1415926 etc etc so what I could always
00:47:13
do is say Hey listen if I have the
00:47:15
fraction pi over 3 you know it's a
00:47:17
smaller fraction three instead of pi
00:47:20
over three and guess what 3 over 3 is
00:47:24
equal to 1
00:47:31
so there is no answer in this
00:47:34
case we've picked a number that is
00:47:37
outside of the domain of AR cosine so
00:47:40
the this does not
00:47:43
exist there is no
00:47:47
answer you have to watch out for that
00:47:50
some of them like for example tangent
00:47:52
are very easy to deal with and they
00:47:53
don't have this problem very frequently
00:47:55
some of them like cosine sign have them
00:47:57
a lot you have to pay close attention to
00:48:00
what you're writing down here's another
00:48:02
interesting problem for you to work
00:48:06
with this time we want to calculate
00:48:09
cosine inverse of cosine of 4 pi/ 3 now
00:48:14
at this point many of you probably
00:48:16
looked at the problem and said oh
00:48:17
obviously the answer is 4 pi over
00:48:21
3 but in fact this is wrong it is not 4
00:48:25
pi over 3
00:48:27
the reason why is that the equation that
00:48:29
you're thinking of the cosine inverse of
00:48:32
cosine of an angle gives us the angle
00:48:34
back only works if the angle is in the
00:48:37
subdomain for cosine in the range of Arc
00:48:41
cosine which we know is 0 to Pi is 4 pi
00:48:45
over 3 in 0 to Pi well let's graph it
00:48:48
really
00:48:51
quickly now if you recall it's a trick
00:48:53
we've used plenty of times 4i over 3 can
00:48:56
be Rewritten it's both a a measurement
00:48:59
of radians and an arc length on the unit
00:49:01
circle and for that reason we can
00:49:03
rewrite it as 4 over3 * pi and it still
00:49:07
makes sense to us if you look at it this
00:49:09
way this means that when we go through
00:49:11
the arc to make the angle 4 pi over 3
00:49:14
we're going to go through an arc that's
00:49:16
4/3 the length of Pi or in other words
00:49:18
slightly bigger than Pi so what we're
00:49:21
really talking about in fact is an angle
00:49:24
that falls into quadrant 3
00:49:29
this right here is 4 pi over
00:49:35
3 I recommend you double check me when I
00:49:37
say things like that but you'll quickly
00:49:39
find that it's the
00:49:41
truth okay you say this is a problem I
00:49:44
don't know what the answer is going to
00:49:46
be then I know that cosine of 4i over 3
00:49:49
will give us answers down here you can
00:49:51
actually figure out what this terminal
00:49:52
point is and I will leave that to you
00:49:54
guys to think about the hint I would
00:49:57
give you if you want to use that is to
00:49:59
look for a reference
00:50:03
angle and you will notice if you start
00:50:05
working your calculations here that
00:50:07
since 4 pi over 3 is bigger than Pi the
00:50:10
reference angle can be found by taking 4
00:50:12
pi over 3 and subtracting PI from it
00:50:15
which will give us pi over
00:50:18
3 but there's actually an easier way to
00:50:21
do this than to worry about calculating
00:50:23
cosine of 4i 3 and then trying to
00:50:26
calculate cosine inverse of whatever
00:50:28
number we get see here's something that
00:50:30
we know and we've talked about many
00:50:32
times if I have an angle and I reflect
00:50:36
it across the xaxis like I'm about to do
00:50:39
right now like
00:50:41
this even though there are going to be
00:50:44
some changes we're now no longer below
00:50:46
the x-axis we're above the x-axis so
00:50:48
that means that we went from a negative
00:50:50
yalue for our terminal point to a
00:50:53
positive y-value for our terminal point
00:50:55
is there any change to the x coordinate
00:50:58
no the x coordinate for this blue point
00:51:02
is exactly the same as the x coordinate
00:51:04
for this red Point down here in fact if
00:51:08
I were to start calculating you'd very
00:51:10
quickly find out that if I take cosine
00:51:14
of 4 pi over 3 or cosine of whatever
00:51:17
this blue angle is I will wind up
00:51:20
getting exactly the same answer so now
00:51:24
here's the only question
00:51:26
what is this blue angle well because of
00:51:29
the way that I've reflected things here
00:51:31
the blue angle and the red angle should
00:51:33
have exactly the same reference angle
00:51:35
which is to say the reference angle here
00:51:38
should be pi over 3 and I'll bet you
00:51:41
dollars to Donuts if you realize that
00:51:44
the angle that I'm interested in is an
00:51:47
angle in quadrant 2 with a reference
00:51:50
angle of pi over 3 you will quickly
00:51:52
figure out the right answer it should be
00:51:55
that this blue angle is 2 piun
00:52:01
3 why is that significant because now I
00:52:05
can rewrite this problem what I'm going
00:52:07
to do is the following I'm going to
00:52:09
still write cosine inverse of cosine of
00:52:13
some value but because I know that
00:52:15
cosine of 4 piun over 3 and cosine of 2
00:52:19
piun over 3 give me the same answer they
00:52:22
correspond to point uh coordinates of
00:52:24
points with the same x coordinate
00:52:27
there is no difference between writing
00:52:29
what I was given and what I've written
00:52:31
here in
00:52:32
blue now I'll ask you this is 2 pi over
00:52:36
3 in the subdomain for cosine is it in
00:52:40
in other words the the range for R
00:52:43
cosine you betcha and now the property
00:52:45
from page to applies these two functions
00:52:48
undo each other and I'm simply left with
00:52:50
2 pi over
00:52:55
3 Let's do at least one more problem
00:52:58
before we call it quits this video is
00:53:00
getting plenty long but I want to make
00:53:01
sure that I have as much information in
00:53:03
front of you as possible and I want to
00:53:05
make sure I practice this skill again so
00:53:07
I have another exercise for us almost
00:53:10
the same but this time we're calculating
00:53:12
sign inverse of s of 4 pi over
00:53:15
3 well I already know that I'm running
00:53:17
into the same problem here that I did up
00:53:20
above 4i 3 does not belong to the range
00:53:23
of Ark sign so I can't simply say the
00:53:26
answer is 4 pi over 3 it does not work
00:53:28
that way that means I'm going to have to
00:53:31
do some rewriting again so here's what
00:53:34
I'm going to do just like last time I'm
00:53:38
going to go ahead and draw the angle so
00:53:40
let's do that really
00:53:43
quickly okay we have 4 pi over 3 drawn
00:53:47
again and because we've already talked
00:53:49
about this I've noted the reference
00:53:51
angle for 4 pi over 3 is pi over 3 now
00:53:55
last time what we did is as we said Hey
00:53:57
listen I'm going to rewrite my equation
00:53:59
because I happen to know that cosine of
00:54:02
4i 3 and cosine of 2 pi over 3 are the
00:54:05
same the reason being they are
00:54:08
reflections of one another across the x
00:54:10
axis and an xais reflection does not
00:54:13
change the x coordinate in other words
00:54:16
it does not change
00:54:17
cosine unfortunately we saw in the same
00:54:20
example that the x-axis Reflections do
00:54:23
change the value of sign s down here at
00:54:27
4 piun over 3 is negative sign up here
00:54:29
at 2 piun over 3 is positive but there
00:54:31
is another type of reflection we could
00:54:33
do and some of you may have already
00:54:35
figured out this is what was going to
00:54:36
happen if I reflect across the y AIS
00:54:40
this time notice the x value changes on
00:54:44
one side it's negative on the other side
00:54:46
it's positive but does the Y value
00:54:48
change no it does not symmetry of the
00:54:51
unit circle tells us this is going to be
00:54:53
a point that has the same y-coordinate
00:54:55
as our red point over here we also know
00:54:59
that when we're talking about sign sign
00:55:02
is restricted to the right hand side of
00:55:04
the unit circle so we're in the right
00:55:05
spot and to get down into Quadrant 4 we
00:55:08
have to go in the negative
00:55:10
Direction plus my red angle and my blue
00:55:13
angle must have exactly the same
00:55:15
reference angle so doesn't that
00:55:20
mean that the reference angle here is
00:55:22
telling us that this angle here is pi
00:55:25
over 3
00:55:27
yes it is telling us that so how do we
00:55:30
rewrite this problem well we write
00:55:33
exactly the same expression that we were
00:55:35
given except that we say Hey listen I
00:55:38
don't need to take s of 4 pi over 3 I
00:55:41
would get the same answer if I took s of
00:55:44
pi over
00:55:47
3 now I've Rewritten the equation it's
00:55:51
not going to change my answer these two
00:55:52
things are exactly the same but now that
00:55:55
I'm looking at at the second equation
00:55:57
notice that the angle on the inside is
00:56:00
an angle in the range of Ark sign since
00:56:04
we are now looking at ARK sign of sign
00:56:07
of an angle and the angle obeys our
00:56:09
rules now I can simply let Ark sign and
00:56:12
sign annihilate each other and so the
00:56:14
answer becomes piun over
00:56:19
3 and with that I think that's almost
00:56:22
all the time we have a couple of quick
00:56:24
notes for my student students you may be
00:56:27
wondering uh what other problems there
00:56:29
might be in this section that you need
00:56:31
to worry about the only other ones that
00:56:33
we have not touched are feeding values
00:56:36
to arc sign Arc cosine Etc on your
00:56:38
calculator now because of the way this
00:56:41
video format works out I can't really
00:56:43
show those to you in person however if
00:56:45
you have the ti3 x2s first of all notice
00:56:49
that when you're looking for these
00:56:51
inverse trig functions you should find
00:56:53
them by locating first the original trig
00:56:55
function like s cosine Etc and then
00:56:59
simply hitting second followed by the
00:57:01
appropriate trig function so if I press
00:57:03
the second button on my calculator and
00:57:05
then sign I should be dealing with arc
00:57:07
sign now no problems the next thing I
00:57:10
want to address is that there are more
00:57:12
identities I mentioned earlier that
00:57:14
there were equations that I wasn't going
00:57:16
to be showing because I didn't find them
00:57:18
to be as useful and I showed you why I
00:57:21
also have some other ways and some other
00:57:25
uh relationships we can use you may be
00:57:27
wondering for example could I do a
00:57:29
similar trick to what I did in these
00:57:31
last two examples if I worked with
00:57:33
Tangent yes there is a trick for working
00:57:36
with Tangent as well however we've run
00:57:38
out of time I feel like an hourlong
00:57:40
video which we pretty much have here is
00:57:42
plenty long enough instead I will give
00:57:45
anybody who wants to a chance to ask me
00:57:47
questions either in the comment section
00:57:48
of this video or in canvas where USF
00:57:51
holds its classes for now that's all the
00:57:54
time I've got so everybody thank you so
00:57:56
much for your attention thank you for
00:57:58
your continued hard work if you have
00:58:00
questions feel free to reach out to me
00:58:02
and until I see you next time happy math