Le Chatelier's Principle Lab with Cobalt Complex Ions

00:10:10
https://www.youtube.com/watch?v=crr5ZMHCJ_Y

Resumo

TLDRCe laboratoire explore une réaction chimique à l'équilibre entre deux complexes de cobalt, en utilisant des changements de couleur pour observer les effets des différents réactifs et conditions. En ajoutant de l'acide chlorhydrique, on favorise le complexe bleu, tandis que l'ajout d'eau favorise le complexe rose. D'autres tests avec du nitrate d'argent et des variations de température montrent comment ces facteurs influencent l'équilibre, permettant de déterminer si la réaction est endothermique ou exothermique. Les résultats soulignent l'importance de la théorie du champ cristallin dans l'interprétation des changements de couleur.

Conclusões

  • 🔬 Étude de l'équilibre chimique entre complexes de cobalt.
  • 🌈 Changements de couleur indiquent le côté favorisé de la réaction.
  • 🧪 L'acide chlorhydrique favorise le complexe bleu.
  • 💧 L'eau favorise le complexe rose.
  • ⚗️ Le nitrate d'argent provoque un changement vers le rose.
  • 🌡️ La température influence l'équilibre de la réaction.
  • 📊 La théorie du champ cristallin explique les couleurs observées.
  • 🔄 Les tests montrent des déplacements d'équilibre clairs.
  • ❄️ Le froid favorise le complexe rose, le chaud favorise le bleu.
  • 📚 Comprendre si la réaction est endo ou exothermique.

Linha do tempo

  • 00:00:00 - 00:05:00

    Dans ce laboratoire, nous étudions une réaction chimique à l'équilibre entre deux formations d'ions complexes de cobalt. En ajoutant de l'acide chlorhydrique, nous observons un changement de couleur vers le bleu, indiquant une formation accrue du complexe de chlorure de cobalt. En ajoutant de l'eau, la couleur revient au rose, favorisant le complexe de cobalt avec l'eau. Ces changements de couleur illustrent les principes de la théorie du champ cristallin et les déplacements d'équilibre en réponse à des stress externes.

  • 00:05:00 - 00:10:10

    Dans le troisième test, l'ajout de nitrate d'argent provoque la formation d'un précipité et un changement de couleur vers le rose, indiquant un retour à l'état réactif. Enfin, en utilisant un bain chaud, nous observons un déplacement vers le complexe bleu, tandis qu'un bain froid favorise le complexe rouge. Ces expériences démontrent comment la température influence l'équilibre chimique et permettent de déterminer si la réaction est endothermique ou exothermique.

Mapa mental

Vídeo de perguntas e respostas

  • Quel est l'objectif principal de ce laboratoire ?

    Étudier une réaction chimique à l'équilibre entre deux formations d'ions complexes de cobalt.

  • Comment les changements de couleur aident-ils à déterminer l'équilibre ?

    Les changements de couleur indiquent quel côté de la réaction est favorisé.

  • Que se passe-t-il lorsque de l'acide chlorhydrique est ajouté ?

    Il y a un déplacement vers le complexe bleu de chlorure de cobalt.

  • Quel effet a l'ajout d'eau sur la réaction ?

    Il favorise le complexe rose de cobalt.

  • Que montre l'ajout de nitrate d'argent ?

    Il provoque un changement de couleur vers le rose, indiquant un déplacement vers les réactifs.

  • Comment la température affecte-t-elle l'équilibre ?

    L'augmentation de la température favorise le complexe bleu, tandis que la diminution favorise le complexe rose.

  • Qu'est-ce que la théorie du champ cristallin ?

    Elle explique les changements de couleur en fonction de la répartition des ligands dans les orbitales d.

  • Comment déterminer si la réaction est endothermique ou exothermique ?

    En observant les effets de la température sur l'équilibre.

  • Quel est le rôle du chlorure de calcium dans l'expérience ?

    Il dissocie en ions, favorisant la formation du complexe bleu.

  • Pourquoi le nitrate d'argent est-il conservé dans une bouteille sombre ?

    Pour protéger les ions argent des effets de la lumière.

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Legendas
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Rolagem automática:
  • 00:00:06
    in this lab we will be studying a
  • 00:00:08
    chemical reaction at equilibrium between
  • 00:00:10
    two complex ion formations of
  • 00:00:12
    cobalt because they form complex ions
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    with water and or chloride ions very
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    favorably we can see which side of the
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    reaction is favored by the color changes
  • 00:00:23
    due to Crystal field Theory which is not
  • 00:00:25
    part of this um lab but we're going to
  • 00:00:28
    be studying later's PR ible and noticing
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    at equilibrium if a stress is made and
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    let's say a stress is made that forces
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    the reaction to go thermodynamically to
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    the right we should be able to see a
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    nice blue color because the reactants
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    get used up and will make more products
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    which will be of course that complex
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    with the chloride iion as chloride with
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    that ligan and of course back at
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    equilibrium if we do something that
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    favors the reverse um reaction where
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    we're going to make more
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    of the um Red by using up the reactants
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    and we will make more of the Cobalt
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    complex that has the water surrounding
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    it as the ligan which will be red we can
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    observe these shifts in equilibrium so
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    let's get
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    started so just to show you uh this is
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    the color or Baseline colors of the
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    Cobalt complex with water and this is
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    the color nice blue color of the Cobalt
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    complex uh with the chloride ion so
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    clearly you can see who's favored and by
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    looking at these colors and this is I
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    believe a purple color although I have
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    difficult time with colors of the
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    equilibrium mixture of both all right so
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    we're going to put out some test tubes
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    here and we're going to follow our
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    procedure as follows so here's our four
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    test
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    tubes and again right now we see the
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    pink color so all these test tubes
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    currently have a lot more of the
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    reactants and products as by the uh pink
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    color favoring the Copp complex with
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    water so we're going to Vin our first
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    test and we're going to just uh add some
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    hydrochloric acid into the first test
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    tube and doing so we see that
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    thermodynamically there is a shift from
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    this
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    reaction going to the side with the blue
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    compound so now we're making a lot more
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    cobalt chloride complex the complex that
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    is blue
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    okay and and very clearly you should be
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    able to figure out in your lab who is
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    being used up and who's being
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    [Music]
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    increased all right so in test tube two
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    we're going to add some calcium
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    chloride and we'll add some more and we
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    should be looking at the bottom of the
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    test
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    tube and the calcium chloride is going
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    to dissociate into its ion that's
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    important you understand into the
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    calcium plus two and the chloride
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    negative ions all right calcium is a
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    salt all right and as I probably bring
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    this closer to us we can see that the
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    bottom of the test tube show shows a
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    favored thermodynamic pathway meaning we
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    see a shift toward the blue side we are
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    making a lot more of that Cobalt ion
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    complex with the chloride
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    ion so clearly you are now shifting one
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    way now of course there's not enough
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    chloride ions to make full test tube go
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    but right where the salt is you can
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    clearly see there is some shift that
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    favors the formation of the blue complex
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    and you should be able to know which
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    side was shifting and in your lab or
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    which reactants and products are going
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    up or going down because of that all
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    right so that's one and two test now
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    we're going to grab test two number one
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    again and we're going to do another test
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    here
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    at some
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    point all right so here comes test tube
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    one again which we can see is clearly
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    favored all right with the blue compound
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    all right and uh now we're going to add
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    some
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    water all right so now adding some
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    Poland Spring water and again this is
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    not a uh uh they didn't pay us any money
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    to do this but we're going to add some
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    water and by adding water you can see
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    definitely a shift toward the pink uh
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    Cobalt complex and that pink Cobalt
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    complex um is on the reactant side so
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    again you should be able to figure out
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    where the reaction is Shifting to by uh
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    whether we making a pink or blue complex
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    here all right and again these colors
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    are due to Crystal field Theory where
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    we're drawing in the lians okay into the
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    D's orbitals and causing the D's to
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    split pretty cool stuff to go through so
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    test tube three here okay we're going to
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    add hydrochloric acid which we've done
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    already before and we're going to see a
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    shift um to that favors um the cobalt
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    chloride complex and you should know
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    what that shift does and now part of the
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    same test now is we're going to add some
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    silver
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    nitrate notice the silver nitrate bottle
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    when it comes into play here has a is a
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    um dark bottle that prevents uh light
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    from getting in too much cuz the silver
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    iron are affected by the Light any case
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    you see me adding some silver nitrate
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    and clearly I see some solid developing
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    as we like to call a precipitate and
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    that
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    precipitate is building up as I add more
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    silver nitrate and I also see a color
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    change here okay as I keep adding more
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    silver
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    nitrate I see it going from this blue
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    complex back to the pink side so I
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    definitely see a pink color developing
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    here as we add some silver nitrate so
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    probably going to bring this up to you
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    and see up close and personal what this
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    looks
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    like and there she is and you can see
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    the solid on the bottom the solid
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    definitely has a white color okay but
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    that's not what's affecting the color
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    this definitely went pink showing us a
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    definite shift in equilibrium to the um
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    Cobalt complex that has a pink color and
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    you should make the appropriate markings
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    in your
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    lamp something about making this
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    precipitate cause the shift to favor the
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    formation of the um reactants the
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    original reactants something to think
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    about there what did we do there that
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    caused that reaction to shift to the uh
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    side that produced the pink complex
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    silver nitrate H we should know about
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    the uh solubility PR uh rules of
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    solubility and what the silver ion must
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    have done okay so our final test now is
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    to put our test Tu 4 which is favoring
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    the pink side and I'm bringing a thermo
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    um an infrared thermometer to show you
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    that the um room or the board behind you
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    is 25.5 de C and the and the water I'm
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    bringing here is 76° C so I'm going to
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    use a hot bath and in this test we're
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    going to put the test tube four in the
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    hot bath and we're going to see what
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    kind of color change will happen now
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    we're changing the temperature here so
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    we're actually going to shift not so
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    much the equilibrium in truth we're
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    actually changing the equilibrium
  • 00:07:42
    position to favor one side or the other
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    by adding heat okay we are definitely
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    Shifting the equilibrium to a new
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    position that's favoring if you can see
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    the blue Co cobalt chloride complex all
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    right and that tells you something about
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    where
  • 00:07:59
    the heat is you know something about L
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    sher's principle you increase the
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    temperature the reaction is going to
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    shift to always do the opposite it's
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    response is opposite so looks like it's
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    shifting in response increasing the
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    temperature which means it's trying to
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    probably relieve that temperature and
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    this should tell you where the heat is
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    in this reaction okay is the heat go on
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    the reactant side or the product side
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    one of the questions in the lab okay is
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    to find out whether the board reaction
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    is endo and EXO and right here these
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    tests are telling you all right so in my
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    second test I'm going to add a cold
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    water bath and this test should also
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    support my understanding uh so here I
  • 00:08:41
    have my U infrared thermometer I get
  • 00:08:43
    about 9° of my ice bath here and I put
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    my my warm solution back into the ice
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    bath and we can probably guess what's
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    going to happen here and lowering the
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    temperature the reaction's going to
  • 00:08:56
    shift to do the opposite probably to to
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    um increase the temperature so it's
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    going to
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    favor
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    whatever shift of equilibrium that
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    favors um the increase in temperature or
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    the exothermic way you should know
  • 00:09:12
    decrease in the temperature is the
  • 00:09:14
    stress the reaction is going to changes
  • 00:09:15
    equilibrium to to do the opposite and
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    that hint of what's Happening Here
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    should tell you from the ice bath test
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    and the um hot bath test where the heat
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    goes in the reaction side is the forward
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    reaction EXO or is the forward reaction
  • 00:09:33
    Endo all right and we can clearly see
  • 00:09:36
    that the cold water bath made uh and
  • 00:09:39
    shifted the equilibrium to favor the red
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    complex all right and that's essentially
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    this lab from these uh tests independent
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    tests you should have be able to figure
  • 00:09:52
    out where the shifts have occurred and
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    who's increasing and decreasing and
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    definitely whether the forward reaction
  • 00:09:57
    is endo or EXO thermic all the players
  • 00:10:01
    involved are taking their bows here I
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    guess I left the water out hope this
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    helped
  • 00:10:07
    [Music]
Etiquetas
  • chimie
  • équilibre
  • cobalt
  • complexes
  • réaction
  • couleur
  • acide chlorhydrique
  • nitrate d'argent
  • température
  • théorie du champ cristallin