00:00:18
hello everybody Welcome to vantu telu
00:00:20
channel this is your master teacher for
00:00:22
physics K maam
00:00:27
ient electricity class
00:00:46
current
00:00:49
electricity where is
00:00:53
it
00:00:56
okay current
00:00:58
electricity
00:01:04
current
00:01:18
[Music]
00:01:25
electricity
00:01:28
electri
00:01:35
dri
00:01:42
electricity good morning
00:01:45
everybody okay
00:01:53
so resistance ohms
00:01:58
law
00:02:01
questions combination of
00:02:04
resistors combination of
00:02:24
resistors kof's law yes another
00:02:28
guaranteed question
00:02:38
application wistone
00:02:40
bridge and meter
00:02:43
Bridge so
00:02:54
lesson ma'am Mains key timable P please
00:02:58
Mains key time table press
00:03:01
I'm actually not feeling well at
00:03:18
all that is my condition right now
00:03:26
so that's it okay but Sunday
00:03:36
elect
00:03:47
exam so current electricity let us start
00:03:51
with
00:03:58
electric
00:04:01
because this
00:04:08
is okay let us
00:04:11
try just give me one
00:04:23
minute scalar
00:04:25
quantity with
00:04:28
Direction
00:04:30
Direction scal quantity so electric
00:04:33
current scal quantity
00:04:43
Direction always take
00:04:54
convention
00:04:58
positive
00:05:07
current it flows from high
00:05:12
potential high potential to low
00:05:22
po negative
00:05:25
low so high potential and low potential
00:05:31
electrical
00:05:33
flow electri flow of
00:05:52
electrons flows from higher potential to
00:05:55
lower potential higher
00:05:58
potential
00:06:23
I
00:06:28
start
00:06:58
number
00:07:28
r
00:07:29
at
00:07:36
least
00:07:43
okay
00:07:58
cel
00:08:05
application examination
00:08:24
ENT first of all number
00:08:28
of
00:08:32
okay
00:08:45
so symb capital letter A okay I ere symb
00:08:52
capital capital letter a i basic formula
00:08:56
I equal to Q by T amount of charge
00:09:00
flowing across a cross-sectional area in
00:09:03
a unit time for
00:09:22
example
00:09:28
crosssection
00:09:58
inst average current and total charge
00:10:02
the total total charge flowing by total
00:10:04
time taken entire
00:10:13
charge inous
00:10:16
current Tous current instantaneous
00:10:21
current and I
00:10:24
instantaneous I instantaneous
00:10:28
instantaneous
00:10:29
Delta Q by delta T limit delta T tends
00:10:34
to Z delt T time when it approaches to
00:10:38
very small
00:10:45
amane so I
00:10:48
instantaneous DQ by
00:10:51
DT so Q is given as function of time Q
00:10:56
is equal to 3 t² - 2T a tus
00:11:21
balal
00:11:27
I
00:11:29
T So current is given as function of
00:11:33
time when current is given as function
00:11:35
of time
00:11:43
then right
00:11:52
so is equal to 3 t² - 2T and is uh Q is
00:11:58
given as function of
00:12:27
applications
00:12:37
so
00:12:40
electric so if number of
00:12:44
charges
00:12:53
number
00:12:57
number uh Q is equal to n into e low n
00:13:02
is equal Q by E the number of
00:13:09
charges
00:13:11
number so IAL Q
00:13:22
by n is equal to I into T by
00:13:26
E I hope e and
00:13:29
1.6 into
00:13:31
10us
00:13:52
okay
00:13:54
question find the
00:13:56
current find the current
00:13:59
current when an
00:14:01
electron when an electron is
00:14:08
revolving revolving in a circular
00:14:14
path circular path of radius
00:14:19
R radius R okay R
00:14:27
radius
00:14:53
so linear velocity angular velocity
00:14:56
normal I equal Al Q
00:15:04
elect
00:15:24
El okay so Q by circular path
00:15:38
so
00:15:40
T
00:15:43
2 if T = 2 pi by
00:15:49
Omega IAL Q by 2 by
00:15:57
omeg 2 Omega Omega
00:16:01
2 if Omega equal 2 f 2 pi 2 cancel IAL Q
00:16:09
into
00:16:13
F electric current Char
00:16:21
frequency uh I is equal to Q into F
00:16:25
electric current is equal to charge into
00:16:27
frequency
00:16:29
e formula electric current in terms of
00:16:32
frequency e formula electric current in
00:16:35
terms of time period next e formula
00:16:39
electric current in terms of angular
00:16:43
velocity electric current in terms of
00:16:45
angular
00:16:51
velocity if Omega equal to V equal R
00:16:55
Omega Omega equal V by r
00:16:59
v = r Omega omegal V by R substitute
00:17:04
substitute IAL Q into V by 2i
00:17:10
R so we have written so many varieties
00:17:13
electric current in terms of time period
00:17:16
electric current in terms of angular
00:17:18
velocity electric current in terms of
00:17:20
angular frequency electric current in
00:17:23
terms of linear
00:17:27
velocity
00:17:57
next
00:18:05
2
00:18:07
andal basic
00:18:27
first
00:18:49
velocity drift
00:18:57
velocity
00:19:23
meaning 10us 4 me speed electr
00:19:29
so 10us
00:19:31
4
00:19:33
0.1
00:19:57
me
00:20:24
cond same
00:20:27
conductor
00:20:57
con
00:21:20
first of
00:21:27
all start so initial velocity Z from
00:21:32
equation v = u + a v u u
00:21:41
velocity a
00:21:51
into to the mean time or mean relaxation
00:21:57
time
00:22:00
to is
00:22:02
called relaxation
00:22:07
time relaxation time to relaxation
00:22:13
time so
00:22:16
relaxation
00:22:19
rela initial position
00:22:26
final
00:22:57
Rel
00:23:08
AAL
00:23:12
e AAL EQ by T okay EQ
00:23:24
by
00:23:26
chares
00:23:28
so since
00:23:31
qal
00:23:43
electron Small E by m AAL to EQ by m
00:23:50
sorry a equal to EQ by
00:23:54
m EQ by m a Al to EQ by m yes correct
00:24:00
shanuka uh sorry
00:24:21
shakala M
00:24:23
into relaxation
00:24:26
timey mass of
00:24:32
electron
00:24:35
El
00:24:38
next relaxation time equal VD drift
00:24:42
velocity into mass of electron by
00:24:45
capital E into small
00:24:48
e okay so relaxation formula
00:24:56
okay electric
00:24:59
current in terms of drift
00:25:02
velocity
00:25:18
next5 please
00:25:19
tell
00:25:26
75
00:25:49
next electric
00:25:51
current in terms
00:25:55
of drift velocity
00:25:58
electric current in terms of drift
00:26:00
velocity electric current in terms of
00:26:03
drift velocity already coms electric
00:26:06
current drift velocity relation very
00:26:09
famous relation I is equal to NE a VD
00:26:24
iology electric current n number of
00:26:27
charges
00:26:29
e important n number of
00:26:34
charges e 1.6 into 10 power - 19 Kum a
00:26:41
area of
00:26:44
crosssection
00:26:50
crosssection of cross-section Place L
00:26:53
always try to write p r squ area of CR
00:27:15
CR drift velocity okay
00:27:24
so
00:27:26
Elm
00:27:29
elect so
00:27:35
next current density something
00:27:38
called current
00:27:41
density current
00:27:46
density so
00:27:49
currrent density basic formula current
00:27:52
density is equal to current by area
00:27:57
current density is equal to current by
00:28:00
area IAL J into
00:28:17
a so IAL j
00:28:26
a
00:28:30
Bas
00:28:32
Vector
00:28:45
vect okay so electric current in terms
00:28:49
of current
00:28:56
density current density
00:29:03
electri okay current density key
00:29:07
relation
00:29:10
between relation between J Bar and E bar
00:29:16
e bar and electric field current density
00:29:25
electric Vector form
00:29:29
of OHS
00:29:31
law
00:29:32
OHS Vector
00:29:46
form
00:29:47
Jal Sigma into
00:29:51
e okay Le Sigma is equal to J Bar by e
00:29:58
bar J current density e electric field
00:30:03
Sigma
00:30:05
Sigma
00:30:08
conductivity
00:30:10
Sig
00:30:16
conductivity reciprocal of resistivity
00:30:19
is called
00:30:21
conductivity Sigma is equal to 1 by row
00:30:25
Sigma is equal to 1 by row
00:30:28
row
00:30:31
resistivity reciprocal of conductivity
00:30:34
is called
00:30:36
resistivity resistivity Sigma is equal
00:30:40
to 1 by row ma already class
00:30:43
beginning electromagnetic waves Sunday
00:30:46
morning
00:30:47
11:00 electromagnetic waves Sunday
00:30:50
morning
00:30:53
11 next so
00:30:56
res
00:30:58
substitute yes J Bar is equal to e bar
00:31:03
by row Sigma 1
00:31:08
by okay J equal e into e
00:31:21
by
00:31:25
Mobility symbolize
00:31:36
movement of electron is called Mobility
00:31:38
Mobility
00:31:41
symbility Formula Drift velocity by
00:31:44
electric
00:31:46
field Mobility Formula Drift velocity by
00:31:50
electric
00:31:56
field
00:32:26
elect
00:32:51
right ohms
00:32:54
law so OHS law
00:33:03
const
00:33:05
temp
00:33:11
temp
00:33:15
con so at constant temperature it is V
00:33:19
is proportional to i v equal
00:33:25
i v
00:33:28
potential potential
00:33:30
difference potential difference current
00:33:33
electricity
00:33:42
lesson potential
00:33:53
difference Kiran rava m
00:34:21
G which is reciprocal of resistance is
00:34:24
called
00:34:25
conductance
00:34:28
conductance reciprocal of resistance is
00:34:30
called conductance reciprocal of
00:34:33
resistivity is called
00:34:35
conductivity reciprocal of resistivity
00:34:38
is called conductivity reciprocal of
00:34:41
resistance is called
00:34:55
conduct
00:35:25
pleas
00:35:29
resistance
00:35:31
Ral r l by
00:35:36
a okay
00:35:38
rity and
00:35:41
also is equal to R A by l r r a by L the
00:35:48
L length of the
00:35:54
conductor we cannot decide formula
00:36:01
low formula low R A
00:36:12
by Point
00:36:14
resistivity does
00:36:16
not
00:36:18
depend does not depend
00:36:21
on
00:36:24
Dimensions resistivity does not depend
00:36:27
on Dimensions
00:36:29
Dimensions length and area of
00:36:32
crosssection
00:36:34
dep of a
00:36:37
conductor
00:36:40
conductor L area of
00:36:49
cross depends
00:36:52
on row only depends on temp
00:36:57
temperature
00:36:59
temperature R
00:37:01
the nature of the
00:37:11
material
00:37:21
temperature 2 me area of crosssection a
00:37:26
l
00:37:29
what
00:37:44
the
00:37:47
material
00:37:49
material
00:37:54
Mar material Mar
00:38:00
resistivity
00:38:03
symb
00:38:05
resistivity resistivity
00:38:10
Maru so
00:38:23
materiality okay so resistivity
00:38:36
so variation
00:38:40
of variation of R and row with
00:38:52
temperature temperature to resistance
00:38:58
resistivity resistance
00:39:01
resistivity
00:39:02
rtal R into 1 + Alpha into Delta
00:39:08
Theta row T is equal to row not into 1 +
00:39:14
Al into Delta Theta
00:39:18
so linear coefficient thermal properties
00:39:23
of matter Al Bet
00:39:25
G alpha alpha and coefficient
00:39:32
of coefficient of
00:39:36
thermal
00:39:41
conductivity coefficient of thermal
00:39:44
conductivity R not row not R not
00:39:48
and resistance resistivity at initial
00:39:52
temperature RT R not an resistance at
00:39:57
final temperature
00:40:00
delt final temperature minus initial
00:40:03
temperature
00:40:25
right
00:40:29
right so very sorry
00:40:33
unable
00:40:36
but Source
00:40:39
chap Akira
00:40:55
MO
00:41:25
fre
00:41:55
so resistance
00:42:04
minus r by R into Delta Theta Alpha is
00:42:09
equal roow T minus
00:42:25
roow
00:42:35
factors so
00:42:38
factors
00:42:40
affecting factors affecting
00:42:47
resistance
00:42:48
resistance
00:42:55
res factors dep Basics Basics we know
00:43:02
that R is proportional to L and R is
00:43:07
inversely proportional to area of
00:43:09
crosssection resistance L directly
00:43:12
proportional are of crosssection
00:43:14
inversely
00:43:16
proportional crosssection inversely
00:43:19
proportional then it is inversely
00:43:21
proportional to
00:43:24
r² area
00:43:26
Al
00:43:29
R so
00:43:33
resistance resistance radius resistance
00:43:36
area resistance length
00:43:49
resistance percentage change
00:43:52
question percentage change in resistance
00:43:58
so delt R by R into 100 percentage
00:44:02
change in resistance change in quantity
00:44:05
by original quantity into 100 so Delta R
00:44:09
by R into 100 directly proportional
00:44:13
Delta L by L into
00:44:15
100
00:44:17
are Del R by R into 100 is equal to
00:44:22
Delta a by a into 100
00:44:26
[Music]
00:44:35
delt R by R into 100 equal to
00:44:39
r² 2 into Delta R by R into
00:44:43
100 2 into Del R by R into
00:44:52
100 and dimensions me
00:45:02
di percentage
00:45:06
change is less
00:45:10
than 5% less than less than
00:45:16
5% question percentage change options
00:45:20
low percent change less
00:45:24
5% if percentage change is more than
00:45:28
5% if percentage
00:45:31
change is more
00:45:35
than
00:45:37
5%
00:45:39
0.01% 0 1%
00:45:42
2% 20% 30%
00:45:54
60%
00:45:59
possible YouTube not possible at
00:46:11
all because I'm not able to get
00:46:15
up Hospital morning so that is my
00:46:20
condition
00:46:23
sb3 sb3 and
00:46:34
K RAV n sb3
00:46:39
already
00:46:54
2024
00:46:57
let us
00:47:10
happy
00:47:13
more R2 - R1 by R1 into 100 is equal to
00:47:19
L2 - L1 by L1 into
00:47:23
100 so percentage change less than
00:47:29
5% units and dimensions method less
00:47:41
than very very very important
00:47:52
conceptus
00:47:54
butus proportional
00:47:59
to something called recasting of
00:48:04
wi recasting of
00:48:23
wire recasting of a wire
00:48:26
Le
00:48:27
wire is
00:48:32
elongated wire is
00:48:39
elongated
00:48:47
is is
00:48:51
elongated
00:48:54
sentence
00:48:57
wire is
00:48:59
melted and
00:49:03
made and made
00:49:07
into new
00:49:24
wire
00:49:53
so
00:49:54
concept
00:50:01
Mass
00:50:02
constant
00:50:05
Conant R is proportional to l
00:50:10
s
00:50:22
sent
00:50:24
Rec
00:50:26
R is proportional to l
00:50:29
squ r proportional to l
00:50:49
s r is inversely proportional to a
00:50:52
square R is inversely proportional to a
00:50:55
square
00:50:58
radius the radius length area of
00:51:02
crosssection radius length area of
00:51:05
crosssection radius so delt R by R into
00:51:12
100 2 into Delta L by L into
00:51:19
100 delt R by R into 100 is equal to 2
00:51:24
into Del Delta a by a into
00:51:27
100 delt R by R into 100 is equal to 4
00:51:33
into Del R by R into
00:51:38
100 okay
00:51:44
so
00:51:49
differ ma'am I got 465 in first year how
00:51:53
much do I need to score in second year
00:51:55
if you you are in AP y y y TT if you are
00:51:58
in AP try to get 100%
00:52:01
marks if you are in to
00:52:17
get wrong
00:52:24
thinking
00:52:34
that's it
00:52:54
okay
00:53:14
98 prepare for the best
00:53:21
so combination of
00:53:24
resist
00:53:48
combin resistors series parallel
00:53:50
combination L Ro rosan prit MB
00:53:56
offl
00:54:08
exam
00:54:24
okay
00:54:26
combination of resistor L first
00:54:28
combination let us take series
00:54:33
combination series
00:54:39
combination
00:54:50
IND series combination so resistors R1
00:54:54
R2
00:55:24
RB
00:55:32
correct
00:55:47
okay
00:55:54
combin
00:56:01
R1 V1 poal across R2 V2 potential across
00:56:05
R3 V3 potential series
00:56:08
combination potential
00:56:13
divid poal
00:56:18
div across all the resistors so
00:56:22
current IAL i1 Plus
00:56:25
I2 + I3
00:56:29
I
00:56:31
IAL
00:56:39
sorry combin V = V1 + V2 + V3 V
00:56:46
equal R in series combination is equal
00:56:49
to R1 + R2 +
00:56:53
R3
00:57:02
effec crosssection area increase then
00:57:05
mass will change ma'am ra Ragu Ru
00:57:08
crosssectional area
00:57:23
increase M
00:57:30
marama mechanical in South nit Akira
00:57:34
2023 pyq test 70 to 80
00:57:38
marks 70 to 80
00:57:53
marks
00:58:17
allim
00:58:23
okay
00:58:25
question V1 value V2 value V3 value find
00:58:31
the potential difference across R2 find
00:58:34
the potential difference across
00:58:40
R3 V1 equal R1 by R1 + R2 +
00:58:48
R3 into total potential V V2 R2
00:58:55
so R2 by R1 + R2 +
00:58:59
R3 into
00:59:02
V V3
00:59:04
equal
00:59:06
R3 r1+ R2 + R3 into
00:59:13
V shortcut formul
00:59:16
okay combin shortcut
00:59:20
formul so let us go with the parallel
00:59:23
combination
00:59:28
parallel
00:59:34
combination
00:59:52
sobin amount of potential
01:00:07
resist R1 R2
01:00:13
R3 I I
01:00:21
I3 so I I I
01:00:41
difference Remains the Same across every
01:00:45
resistor potential difference
01:00:49
same so
01:00:51
I IAL i1 + I2 +
01:00:55
I3 I equal to V by r v cancel 1 by R in
01:00:59
parall equal to 1 by R1 + 1 by R2 + 1 by
01:01:23
R3
01:01:25
reading question
01:01:50
reading
01:01:53
okay
01:02:07
so
01:02:23
okay
01:02:48
SOC 1 by R1 + 1 by R2 + 1 by R3
01:02:55
into total current I I2 is
01:03:00
equal current divider
01:03:06
circuit current divider
01:03:10
circuit combination potential
01:03:15
div
01:03:17
div current div iul 1 by R2 equal 1 by
01:03:24
R1 + 1 by R2 + 1 by
01:03:28
R3 into total current same
01:03:33
I3
01:03:36
1 by 1 by R1 + 1 by R2 + 1 by
01:03:43
R3 into total current I Okay
01:03:53
so
01:04:17
because
01:04:19
energy by time so power is equal to
01:04:24
electrical energy formula i² r t by T
01:04:29
electrical energy formula J's law of
01:04:34
heating
01:04:39
i i s r t so t t
01:04:45
cancal i² r
01:04:48
formula next IAL V by R substitute i v
01:04:56
rute p = v²
01:05:02
r
01:05:03
Ral V by I
01:05:06
substitute p isal v
01:05:23
i 1 kilowatt hour kilowatt hour is equal
01:05:28
to 3.6 into 10^ 6
01:05:35
JS
01:05:41
number
01:05:43
so power calculation basing on the given
01:05:53
information
01:06:12
electric
01:06:17
cells
01:06:19
EMF V and
01:06:23
potential
01:06:28
potential terminal
01:06:31
voltage terminal
01:06:34
voltage EMF it is electromotive force
01:06:39
the force with which it forces the
01:06:43
electrons to move from one end of the
01:06:45
wire to other end of The
01:06:53
Wire is equal to e minus
01:06:57
I small r n internal
01:07:03
resistance internal
01:07:20
resistance
01:07:22
reaction
01:07:42
okay
01:07:44
oh 3 Vols 1
01:07:52
oh
01:08:01
Capital Ral 8 ohms but small Ral 1
01:08:09
oh 8
01:08:15
ohms 8 OHS 1
01:08:22
oh
01:08:32
Amal e r small
01:08:38
r
01:08:45
resn
01:08:52
extern
01:09:02
[Music]
01:09:11
okay firstent electricity very good at
01:09:22
least
01:09:31
this is the answer for
01:09:39
you cells in series
01:09:41
par cells in
01:09:45
series
01:09:48
combination
01:09:50
cells in parallel
01:09:57
combination
01:09:59
identical
01:10:19
combination series
01:10:22
combination
01:10:24
external
01:10:32
resistance external
01:10:38
resistance Capal external resistance e e
01:10:43
e
01:10:49
e internal resistance smaller identical
01:10:52
C so current current Formula I total
01:10:58
equal to V
01:11:22
total
01:11:31
by internal resistance
01:11:35
extern current in series combination
01:11:38
that's
01:11:39
it internal resistance external
01:11:43
resistance
01:11:44
combin so
01:11:50
NR
01:11:52
connect
01:11:55
wrongly connected
01:11:57
cells out
01:11:59
of n
01:12:01
cells n number of cells low M
01:12:06
cells are wrongly
01:12:10
connected wrongly
01:12:22
connected l
01:12:47
conect so
01:12:52
dou
01:13:17
M into capital E by n - 2 m into small r
01:13:25
cap
01:13:39
okay wrongly connected
01:13:41
okay anyways so series combination
01:13:49
maximum small R much much greater than
01:13:52
capital r r capital r much much greater
01:13:56
than small R
01:13:58
conditions small R much much greater
01:14:00
than capital r capital r negligible n e
01:14:04
by n r so I equal to e by small r
01:14:08
capital r much much greater than small
01:14:11
negligible n e by R IAL n e by R so
01:14:18
maximum current condition condition for
01:14:21
maximum current to flow
01:14:24
maximum current flow Val capital r must
01:14:27
be much much greater than small
01:14:29
R parall combination
01:14:34
easy
01:14:37
resistance intern
01:14:47
resistance n
01:14:52
cells
01:14:55
okay
01:14:57
c internal
01:15:08
resistance small small small e e e
01:15:17
[Music]
01:15:22
e
01:15:29
1.5 2.5 3.5 6.5
01:15:35
10.5
01:15:39
10.5
01:15:52
combin
01:16:00
equal V total by R
01:16:05
total V
01:16:07
total
01:16:16
V is equal to 1 by r + 1 by r + 1 by R
01:16:21
and so on and by R 1 by R effective so R
01:16:27
effective R by n so R
01:16:40
byn IAL
01:16:44
LCM by small R
01:16:50
NR cells in series parall comp
01:16:53
combination lecture
01:16:59
direct
01:17:08
pares years C problems
01:17:22
pleas so
01:17:29
K
01:17:32
kops
01:17:35
so second
01:17:42
so first
01:17:44
law it is also called
01:17:47
as Junction
01:17:52
law it is also called as
01:17:55
KCl current law or it is also called as
01:18:01
current
01:18:06
Lawan
01:18:08
so Loop
01:18:15
Junction any
01:18:21
Junction any Junction
01:18:25
Sigma IAL 0 to IAL n Sigma
01:18:32
I Sigma I equal
01:18:36
to0 Sigma I equal to0 the algebraic sum
01:18:41
of currents at a junction is equal to
01:18:44
zero the algebric sum of currents at a
01:18:47
junction
01:18:51
equal
01:19:05
so. then
01:19:21
I first law
01:19:38
I 4.5
01:19:41
amp 4.5
01:19:44
2 so I2
01:19:47
value
01:19:51
2.5
01:19:54
Junction
01:20:21
important
01:20:39
K's current law next kop Second Law
01:20:47
K's
01:20:49
kops second law kop of second law is
01:20:54
also called as Loop
01:20:58
law
01:21:00
or Loop
01:21:16
voltage
01:21:18
Loop so according to K's Loop law the
01:21:21
albc sum of all the current Potentials
01:21:24
in a closed loop in a closed loop K
01:21:29
condition closed loop sum of potentials
01:21:33
equal to
01:21:36
Z
01:21:51
problem problem in
01:21:53
techniques problem solving techniques
01:21:57
step number
01:21:58
one step number one
01:22:01
always
01:22:05
identify
01:22:08
Junctions Junctions First Step number
01:22:14
two
01:22:17
apply apply Junction law
01:22:21
KCl Junction
01:22:27
Junction so apply
01:22:30
k at those
01:22:47
Junctions first of all step number one
01:22:50
step number
01:22:51
two step number one step number
01:22:55
two
01:22:57
to
01:22:59
identify to identify the
01:23:12
currents number one step number
01:23:15
two number three and step number
01:23:19
three
01:23:21
identify
01:23:23
identify the
01:23:26
loops loops identify Next Step number
01:23:31
four step number four Loops
01:23:35
identify draw a
01:23:51
pathes step number four rules
01:23:56
rules
01:23:58
resist
01:24:15
okay Direction next now green
01:24:21
color
01:24:23
green
01:24:51
color
01:25:17
I and
01:25:19
path are in
01:25:23
same
01:25:27
direction current same
01:25:30
direction I and
01:25:34
path are in opposite
01:25:42
direction current path opposite
01:25:46
direction so
01:25:50
current same
01:26:01
V equal minus i v equal +
01:26:17
I next in case
01:26:20
of cells
01:26:45
Em
01:26:49
Green Green
01:26:51
colores
01:27:13
positive to negative negative to
01:27:16
positive positive
01:27:18
negative posi to negative land potential
01:27:23
decrease negative potential so V equal
01:27:28
minus
01:27:37
E
01:27:46
difference unidentical
01:27:49
let us take an example
01:28:14
also okay so it 1 ohm 2 ohms 3 ohms 4
01:28:21
Ohms
01:28:23
First Step number
01:28:25
one step number one step number
01:28:30
one identify the junction step number
01:28:49
two can I name this as Junction
01:29:07
okay heating effect
01:29:13
ofal i r heating effect of
01:29:19
current
01:29:20
already
01:29:45
equal so
01:29:50
Junction
01:30:17
I
01:30:20
I I
01:30:49
IIs same step number one step number two
01:30:53
currents identification I step number
01:30:56
three identify the loops draw a path
01:30:59
identify the loops
01:31:05
Loop c d
01:31:12
e so
01:31:14
Loop a c d b a a c d b a Iden
01:31:38
opposite
01:31:39
direction so plus 1 into i-
01:31:44
i1
01:31:46
next positive to Nega
01:31:49
landus 10
01:31:52
current opposite direction + 2 into i-
01:31:57
i1 equal
01:32:07
0 a
01:32:09
e f b a a e f b a PA
01:32:19
clockwise current same
01:32:22
- 4
01:32:24
i1
01:32:28
3us 3
01:32:34
i1
01:32:50
10al okay
01:33:08
resistor cell in resistor in cell find
01:33:14
the potential difference between a and b
01:33:17
2 ohm 6 volts 3 ohms 9
01:33:48
Vol so potential V a current path same
01:33:54
direction- 2 I path positive to
01:34:06
negative Direction - 3 i - 2 positive +
01:34:12
9- VB is equal
01:34:15
0
01:34:17
v
01:34:20
v okay
01:34:33
0
01:34:36
85
01:34:46
chap
01:34:47
chap easy to kill and compuls
01:35:00
9
01:35:02
95
01:35:14
95ti
01:35:20
okay okay
01:35:36
okay applications a wheatstone
01:35:44
bridge whe
01:35:46
bridge bridge easy
01:35:49
top Bridge
01:35:59
so brid B arrangement of
01:36:16
resistors p q r s
01:36:32
balanced
01:36:35
condition balanced condition there is no
01:36:38
current flowing through
01:36:50
galvanometer
01:36:51
am
01:37:18
of so i3
01:37:29
I will be equal to
01:37:50
Z
01:37:52
P by
01:37:53
qal R by
01:38:06
s p q p+ q
01:38:10
RS r + s e p + q r +
01:38:16
S so p + Q into r + S R1 R2 by
01:38:25
R1 p + Q + r +
01:38:34
S effective form
01:38:44
okay unbalanced Bridge p is not equal to
01:38:48
R by S unbalanced Bridge
01:38:56
unbalanced
01:39:02
okay
01:39:06
Lo
01:39:12
Loop
01:39:13
next met
01:39:18
Bridge inco
01:39:20
application
01:39:22
meter
01:39:26
Bridge 1 me
01:39:33
L point
01:39:35
B L Lal 100 cm 1
01:39:42
m
01:39:50
1
01:40:14
okay fixed okay physic
01:40:18
fixed left Gap
01:40:22
right
01:40:24
Gap right
01:40:26
Gap
01:40:49
fix
01:40:59
left right that's it so left Gap right
01:41:03
Gap left
01:41:19
Gap
01:41:28
so L1
01:41:30
CM because one one me
01:41:34
fix L2 equal 100us
01:41:49
L1
01:41:51
resistance in left
01:41:54
Gap resistance
01:41:57
in left
01:41:59
Gap by
01:42:04
resistance in
01:42:14
right confusion the left Gap low
01:42:17
resistance the right Gap low resistance
01:42:20
is equal to 2 is equal to L1 by L2 Le L1
01:42:26
by 100us
01:42:49
L2
01:43:15
description current
01:43:19
electricity
01:43:46
electricity current
01:43:48
electricity 10 questions 10 to 15
01:43:51
questions
01:44:13
practice
01:44:15
sorry act
01:44:18
surprise surprise
01:44:21
and dpps are
01:44:26
provided dpps are
01:44:29
provided
01:44:31
with every
01:44:34
class every class
01:44:39
except except IP
01:44:42
classes IP
01:44:49
object
01:45:19
link
01:45:32
assments
01:45:44
ques Chanel
01:45:46
join almost every week 15
01:46:12
elect waves
01:46:19
eles join thank you all thank you guys
01:46:22
Sunday electromagnetic
01:46:26
baves