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[Music]
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understanding how enzymes are inhibited
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has important implications both for our
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understanding of the mechanism of
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enzymatic action and with medical
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considerations in this lecture I will
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talk about two primary things reversible
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enzyme inhibitors and also irreversible
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enzyme inhibitors cells of course rely
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on enzymes to catalyze reactions and
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that reliance on enzymes allows us to be
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able to control cells if we can control
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enzymes and that means it's a
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consideration particularly if we have a
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bacterium for example that we want to
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stop from infecting something or a
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cancer cell that we want to stop from
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spreading
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so inhibiting enzymes is an important
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consideration for us for health purposes
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I want to spend some time talking about
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three different types of inhibition of
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enzymes and the first of these that I'll
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talk about is called competitive
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inhibition you can see this shown
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schematically on the screen the enzyme
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with its normal substrate as shown on
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the left the enzyme binds to the
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substrate and converts the substrate
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into product on the right we see that
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same enzyme that is the target of an
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inhibitor of it and in this case the
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target inhibitor looks like the original
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substrate it fits in the active site of
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the enzyme the same way that the the
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normal substrate did but there's
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something about the inhibitor that the
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enzyme can't manipulate it can't do
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anything with it and that causes the
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enzyme to sorta sit and spin its wheels
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while it's bound to that inhibitor that
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inhibitor is called a competitive
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inhibitor and a competitive inhibitor
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has the properties I've shown here that
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it looks like the substrate and binds to
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the active site now on the screen here
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you can see a couple of different
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molecules the bottom molecule is a
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molecule that's used by an enzyme called
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dihydrofolate reductase the enzyme
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dihydrofolate reductase uses this
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molecule and converts it into a product
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where the product is used to make
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nucleotides very important for
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nucleotides the molecule above it is
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called methotrexate and methotrexate is
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very similar to dye head to
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dihydrofolate however
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there's an important difference to it
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and the difference prohibits the enzyme
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dihydrofolate reductase from acting
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while methotrexate is an inhibitor of
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that enzyme and by inhibiting an enzyme
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that makes nucleotides that specific for
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a cell one could imagine that one could
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stop that self from dividing and that's
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exactly what this inhibitor is used for
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now let's study the effects of that
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competitive inhibitor on an enzyme if we
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take an enzyme and we compare the V
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versus s plot of an uninhibited reaction
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with an inhibited reaction we will get
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something like what we see on the screen
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here now I need to explain how this was
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done I've described how we used say 20
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tubes to generate the data that's used
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to make the first line that is that the
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enzyme plus varying amounts of substrate
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each tube has a different amount of
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substrate and a buffer are used and we
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measure the velocity by measuring the
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amount of products the quantity
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concentration of products produced over
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time if we want to study the inhibitor
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we want the the inhibited reaction we
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want to remember that we want to have
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one variable and the one variable we
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said we have is substrate concentration
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that means that we can't vary the amount
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of inhibitor so when we cheat we do the
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second set of reactions we have the same
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amount of enzyme we have the same buffer
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and we have the same amount of inhibitor
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in each tube but we have varying amounts
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of substrate what happens when we do
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that well when we do that we see that
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the reaction starts off and it's at a
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lower rate that's not too surprising
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because there's inhibitor there that's
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inhibiting enzyme the velocity is lower
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but as we go to increasing amounts of
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substrate we see that the inhibitor
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keeps rising and rising and rising and
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by the end it's actually rising fast
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enough that it is getting in the range
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of the velocity of the uninhibited
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reaction okay we see that this the the
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difference between the two curves is
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decreasing now I'll cut to the chase
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here and I'm cutting to the chase I'll
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tell you that if we go to very very
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large amounts of substrate we will
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discover that the two enzymes have the
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same v-max now why is that the case why
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does a competitively inhibited reaction
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have the same v-max as an as no
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inhibitor whatsoever
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the answer is due to the way that the
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experiment was set up I said that we had
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fixed amount of inhibitor it gigantic
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concentrations of substrate what happens
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well the substrate it's much more likely
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that the substrate will be found by the
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enzyme then the inhibitor will be found
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by the enzymes at low concentrations
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they compete pretty well but at high
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concentrations where I might have a
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million times as much substrate as I
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have inhibitor the difference between
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the uninhibited and the inhibited is
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difficult for me to see in addition to
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the v-max not changing for the a
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competitively inhibit of reaction
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something does change in this reaction
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and the thing that changes is the km
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since the two reactions that is the
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uninhibited and the inhibited reaction
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have the same v-max they have the same
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v-max over two so if we plot on each
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curve the km value which we get from
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v-max over two we discover that the km
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value for the uninhibited reaction is as
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we would expect but the km for the
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competitively inhibit of reaction
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increases now that increase is
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indicating an apparent change in the
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affinity of the enzyme for the substrate
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now that I say apparent because it
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doesn't actually change the affinity of
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the enzyme for the substrate and that's
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a deeper topic that I'll talk about here
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but the apparent km increases making it
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seeing that the enzyme is losing its
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affinity for its substrate this is shown
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graphically in another way using a
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lineweaver-burk plot so remember with a
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lineweaver-burk we take the same data
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that we had for the V versus s plot and
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we invert all the data and then plot
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that on an inverted plot as you see here
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one over V zero versus one over the
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concentration of s when we do that we
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see that not surprisingly the V versus s
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data comes to a line is shown in green
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with a y-intercept corresponding to 1
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over v-max and an x intercept
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corresponding to minus 1 over km when we
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plot the competitive inhibitor we see
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exactly what we learned in the last plot
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which was that the v-max is the same and
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the two lines cross at the y axis and
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since the km value increased for the
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competitive inhibition what we see then
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is that the minus 1 over km gets closer
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to zero the lineweaver-burk plot shows
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us very graphically what's happening
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with that inhibition another type of
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inhibition that's
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important for us to understand is that
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of non-competitive inhibition it's
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fundamentally different from in
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competitive inhibition and we can see it
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depicted on the screen here on the left
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again we have the enzyme with its normal
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substrate which catalyzes a reaction
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however the enzyme has a site on it that
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if is properly targeted by an inhibitor
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the inhibitor can bind to it and keep
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the enzyme from functioning properly
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with the substrate in the active site
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and that's shown in the image on the
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right now when this happens the
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non-competitive inhibitor has a
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fundamentally different way of
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interacting with the enzyme than what we
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saw before they affect it by binding at
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a different location and by binding at a
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different location they do not compete
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okay now this changes the parameters of
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the things that we've been sities that
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we've been studying considerably and
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because the to inhibit err does not
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compete with the substrate and the
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substrate can't out weigh it by adding
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an awful lot more sub by doing a
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reaction with an awful lot more
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substrate it means that in every
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reaction that we do what happens is that
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we're inhibiting a fixed amount of
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enzyme it doesn't matter how much enzyme
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that we add there's always the same
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amount of enzyme inhibited in the first
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reactions the competitively inhibited
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reactions we saw that as we added more
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substrate the substrate how competed the
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inhibitor and it was as if the inhibitor
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disappeared so the quantity of enzyme
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being inhibited was changing the more
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substrate we added the more normal
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enzyme we had with a non-competitive
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inhibitor we don't have that it doesn't
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matter how much substrate we have
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because they're not competing for the
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same site the non-competitive inhibitor
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is always going to knock out the same
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amount of enzyme in every tube
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irrespective of how much substrate is
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added to it that means that we've
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changed the amount of enzyme and if we
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change the amount of enzyme we've
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already talked about the limitations of
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an enzyme and studying it with v-max
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remember the factory analogy and the
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factory analogy I said that if we added
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an extra factory would double the amount
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of product what if the factory only
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worked half a day
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if the factory only worked half a day it
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would make half the amount of product
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we've changed the numbers of workers so
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what if we use enough inhibitor that we
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only have half the amount of enzyme well
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we would change v-max accordingly so
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when we have a non-competitive inhibitor
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we're changing the amount of enzyme and
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then changing the amount of enzyme we
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change the value of V Max so v-max
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decreases for a non-competitive
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inhibitor that wasn't the case for a
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competitive inhibitor right now we can
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only measure km for an active enzyme and
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not surprisingly if we change the amount
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of enzyme km the affinity the enzyme for
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the substrate doesn't change because the
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enzyme is still the enzyme when it's
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active and we're only studying active
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enzyme so the km value does not change
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for non-competitive inhibition on a
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lineweaver-burk plot we see something
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different than we saw with a competitive
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inhibition but consistent with what I
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just told you in green again we see the
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linear a lot the linear plot showing of
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course the uninhibited reaction in blue
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we see the non competitively inhibited
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reaction and we noticed that the two
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lines crossed at minus 1 over km well
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this is consistent with what we learned
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in the last plot which is that the km
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value does not change they should cross
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at that point however we see the blue
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line is has a higher slope than does the
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Green Line meaning that the crossing of
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the y-axis is at a higher point now that
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may seem counterintuitive that if we
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decrease the v-max we actually are
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raising the value of that line but
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remember we're doing a reciprocal so by
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decreasing v-max 1 over v-max actually
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increases okay now the last plot the
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last inhibition I want to do is one
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that's a little harder to get your head
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around and I mainly want to just
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introduce what it does and the effects
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of this inhibitor this inhibitor type of
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inhibition is called uncompetitive and
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uncompetitive is somewhere in between
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the two a uncompetitive Utley inhibited
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reaction occurs by a mechanism that you
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see on the screen the normal substrate
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binds to an enzyme as before but in the
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case of the uncompetitive
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inhibitor it only binds to the es
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complex now that es complex is on the
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way to becoming product and so it's only
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binding at that point so the more es
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complex we have which is what we're
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gonna have with more substrate the more
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es complex we have the more inhibited
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enzyme that we have now that's kind of
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hard to get our heads twisted around
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we're gonna see in fact as we look at
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the plots if that's going to be
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difficult to conceptualize as well let's
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take a look at the kinetics now of an
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uncompetitive reaction compared to that
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of an uninhibited reaction again we're
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plotting V versus s we as we have done
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before the orange plot is the
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uninhibited reaction no inhibitor
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present and we see a normal a hyperbolic
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plot when we plot the uncompetitive
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inhibited reaction however we see
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something that's a little hard to get
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our heads around the problem are the the
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confusion with the uncompetitive
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reaction is that first of all we see
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that it has a lower apparent v-max and
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it does have a lower apparent v-max and
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the other thing that's confusing about
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this is it has a slightly higher
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velocity at lower concentrations and
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that happens actually because the
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uncompetitive inhibitor favors the es
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complex it says if we are increasing the
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percentage of the enzyme present in the
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es complex and that has the effect of
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apparently speeding up the reactions
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which is why that first part of the
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curve the velocity for the uncompetitive
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reaction is higher than it is for the
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the the reaction with no competitor well
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when we do the plots we also see
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something interesting that happens and
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that is that the uncompetitive reaction
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has a lower km value so not only does
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the uncompetitive reaction at high
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substrate concentrations have a lower
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velocity because at higher substrate
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concentrations will have a greater
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percentage of the enzyme in es complex
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which is greater target for the
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uncompetitive inhibitor but we also see
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that the apparent km of the enzyme is
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decreased and again this happens because
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the the inhibitor is favoring the es
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complex it's making it look like the
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enzyme is binding substrate better well
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that can
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using result is reflected in what we see
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on a lineweaver-burk plot on the
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lineweaver-burk plot what we have is
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something that looks like this the Green
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Line again shows the uninhibited
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reaction with what we've seen before the
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one over v-max the intercept on the y
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axis and the minus one over km on the x
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axis the lineweaver-burk plot for the
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uncompetitive reaction shows a value
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higher on the y axis for one of our
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v-max and that's reflective of the fact
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that the v-max has decreased so one of
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our v-max has increased and we also see
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the x axis has moved farther to the left
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meaning minus one over km has farther
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away from zero which is what happens
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when we have a lower km the three
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mechanisms of enzyme inhibition that
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I've talked about so far competitive
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inhibition non-competitive inhibition
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and uncompetitive inhibition are
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fundamentally different from the one I'm
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getting ready to talk about here in each
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of those cases the binding of the
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inhibitor to the enzyme was a reversible
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process the inhibitor could go on but
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the inhibitor could also come off and
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these are very common inhibition
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mechanisms the mechanism getting ready
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to describe here called suicide
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inhibition is different completely from
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them in suicide inhibition what happens
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is the inhibitor that binds to the
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enzyme does so irreversibly and it does
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it irreversibly because the inhibitor
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makes a covalent bond with the enzyme at
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the active site the enzyme can't shake
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the sub that the inhibitor loose and as
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a consequence the enzyme is completely
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put out of action now example of a
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reaction like this occurring is that of
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the action of penicillin which use which
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we use to kill bacteria penicillin works
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because what it does is it inhibits the
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the bacterium's ability to make cell
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walls well cell walls are pretty
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important for cells because without a
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wall you don't have a cell the way that
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this works is penicillin mimics the
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normal substrate that the enzyme that
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makes the cell walls uses that's the
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Pedigo icing chain because penicillin
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resembles that the enzyme binds to it
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like it would bind to the normal
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substrate but penicillin makes the
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covalent bond
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so in suicide inhibition the enzyme is
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completely destroyed and never gets a
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chance to come back into its thing well
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in this
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of lectures what I have talked about are
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different types of inhibition a
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reversible set of inhibitions that
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included a competitive non-competitive
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and uncompetitive and now suicide
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inhibition that is an irreversible
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enzyme inhibition our understanding of
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enzyme inhibition is important for
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anyone interested in understanding the
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mechanism by which drugs work or
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designing drugs themselves
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you
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[Music]